Permabanned
- Joined
- 8 Feb 2004
- Posts
- 4,539
Not sure if there is enough information to solve unless assume 25 goals total.
Can someone help me with a math (fraction) question?
- Thread starter Pocket10s
- Start date
Soldato
- Joined
- 30 Sep 2005
- Posts
- 16,550
Maths question..Check
Posted on the internet..Check
It's BODMAS. It's always BODMAS. Even when it isn't, it is.
Associate
- Joined
- 8 Jul 2005
- Posts
- 1,575
I bet Ray Winstone knows.
Soldato
This is impossible to answer without knowing the total number of goals scored in each half. If 100 goals were scored in the first halves and 400 goals in the second halves, then that would be 500 goals in total, but 1/5 of goals in the first half would not equal 1/5 of goals in the second half. Therefore you cannot just add the two fractions together and get the fraction for both.
Soldato
LOL at the person boasting on the forums about how they taught themselves particle physics rather than playing video games like other losers, and bemoaning how "modern interpretations of the Copehagen Interpretation weren't taught" getting basic maths questions wrong.
Shout out to dl8860 who is the only other person here who noticed the question couldn't be correctly answered.
Soldato
If you read 3/5 as three goals of five scored in total in the frst half, rather than three fifths of some unknown quantity, it works. The problem in this case would then have been the wording of the question.
Soldato
- Joined
- 25 Nov 2005
- Posts
- 12,452
19/40 if we're just taking the fractions as they are
3/5 in first half from top 6
7/20 in second half from top 6
to make 3/5 equivalent to 7/20 we multiply by 4 = 12/20
12 + 7 = 19
20 + 20 = 40
19/40
That only works if you're taking 2 fractions from the same whole, his question takes a whole and splits it into 2 halves essentially making 2 different wholes where one whole is /5 and the other is /20 but we can still use common denominator to find and add the 2 wholes together to make the original whole
3/5 in first half from top 6
7/20 in second half from top 6
to make 3/5 equivalent to 7/20 we multiply by 4 = 12/20
12 + 7 = 19
20 + 20 = 40
19/40
Jesus H Christ this thread is sad.
Some people here must think that 1/2 + 1/2 = 2/4. What's 2/4? Oh yeah, it's 1/2. People here are literally saying 1/2 + 1/2 = 1/2 without realising.
That only works if you're taking 2 fractions from the same whole, his question takes a whole and splits it into 2 halves essentially making 2 different wholes where one whole is /5 and the other is /20 but we can still use common denominator to find and add the 2 wholes together to make the original whole
Caporegime
Surely given the fractions, it is possible to say that the number of goals scored in any half are a multiple of the denominator.
Therefore it doesn't matter how many goals are scored in either half, just the relative fraction of them that were scored by the top teams, as the question wants an answer that is a fraction (eg. doesn't care about the actual number of goals scored).
please, just stop.
Soldato
Nope, you can't compare the fraction of total from the first half with the fraction of total from the second half without knowing how much of the total was in each half.
Here are some examples of the number of goals from each half:
6/10 + 7/20 = 13 goals scored out of a total of 30 (43%)
3/5 + 21/60 = 24 goals scored out of a total of 65 (37%)
6/10 + 70/200 = 76 goals scored out of a total of 210 (36%)
12/20 + 14/40 = 26 goals scored out of a total of 60 (43%)
All of these examples have a number of goals each half which simplify down into the same 2/5 and 7/20 fractions but none of them are equal to 19/40 (47%)
3/5 of the goals in the first half were scored by teams in the top 6. In the second half the teams outside the top 6 scored 13/20... This isn't even fractions really, it's just addition...
It's a bit of a trick question because you can wrongly assume that 3/5 is three fifths of x number of goals, when it clearly isn't. It's 3 of the 5 goals. Without thinking of this way the question makes no sense without a total number of goals for each half.
3 goals where scored by top 6 teams in the first half. 7 scored in the second. So 10 goals out of the 25 scored were scored by a top 6 team. 10/25. Calling it 2/5 is imprecise in this context.
It's a bit of a trick question because you can wrongly assume that 3/5 is three fifths of x number of goals, when it clearly isn't. It's 3 of the 5 goals. Without thinking of this way the question makes no sense without a total number of goals for each half.
3 goals where scored by top 6 teams in the first half. 7 scored in the second. So 10 goals out of the 25 scored were scored by a top 6 team. 10/25. Calling it 2/5 is imprecise in this context.
Soldato
- Joined
- 25 Nov 2005
- Posts
- 12,452
I don't think you understand the question or Math
It's asking you to workout what total 3/5 of 1/2 is with 7/20 of 1/2
You need a common denominator in order to add the 2 fractions together and to make 1/1 where the 1 whole = 40
It does matter. Just imagine multiple scenarios where the number of goals in the first half increases. The more it increases, the closer the top teams' total fraction of goals matches the first half's fraction since the second half's goals become ever more insignificant. ie for a million goals in the first half (and a much smaller amount in the second half), the top teams total fraction will be pretty much 3/5.
Sure, now say that to someone without a maths PhD.
Just stop adding denoms like it's a thing.
Soldato
Oh god, this thread haha
3 goals out of 5
7 goals out of 20
That makes 10 goals scored by the top 6 out of 25 goals.
10/25 = 40%
For those saying that the answer is 19/40, can you tell me how many total goals were scored and how many total goals did the top 6 score?
3 goals out of 5
7 goals out of 20
That makes 10 goals scored by the top 6 out of 25 goals.
10/25 = 40%
For those saying that the answer is 19/40, can you tell me how many total goals were scored and how many total goals did the top 6 score?
Soldato
You're treating the 3/5 and 13/20 as actual numbers rather than fractions. If you interpret it that way then yeah you're right.
Munches internet cookie