13 Apr 2011 at 00:34 #1 mufc802 mufc802 Soldato Joined 1 Jul 2009 Posts 2,678 2x^4+14x^2+24. I'm not sure what to do when the power is greater than 2. Please explain.
13 Apr 2011 at 00:39 #5 mufc802 mufc802 Soldato OP Joined 1 Jul 2009 Posts 2,678 trigger-happy said: c1 mathematics? Click to expand... Yeah I'm trying to teach myself.
13 Apr 2011 at 01:08 #15 mufc802 mufc802 Soldato OP Joined 1 Jul 2009 Posts 2,678 OK I worked it out using my method. So 2x^4 + 14x^2 + 24 A = 2 | B = 14 | C = 24 AC = 48 B = 14 8*6 = 48 & 8+6 = 14 (2x^4 + 8x^2) + (6x^2 + 24) 2x^2(x^2 + 4) + 6(x^2 + 4) (2x^2 + 6) (x^2 + 4) or 2(x^2 + 3) (x^2 + 4) So is this the correct method or is there a better way?
OK I worked it out using my method. So 2x^4 + 14x^2 + 24 A = 2 | B = 14 | C = 24 AC = 48 B = 14 8*6 = 48 & 8+6 = 14 (2x^4 + 8x^2) + (6x^2 + 24) 2x^2(x^2 + 4) + 6(x^2 + 4) (2x^2 + 6) (x^2 + 4) or 2(x^2 + 3) (x^2 + 4) So is this the correct method or is there a better way?