I understand this wavefore to be even therefore i'm going to derive an expression (An) in order to find the ampiltude of the fundamental and the harmonics

The voltage at the peak is 12v

So, let me see if I have this right sorry of for the long maths and or bad formatting

An = 1/Pi (integrale with pi/03 and -pi/0.3)12cos (ntheta)dtheta

An = 12/Pi [sin(ntheta)/n](integrale Pi/0.3 and -Pi/0.3

An = 12/nPi [ sin(nPi/0.3) - sin(-nPi/0.3)]

An = 12/nPi [ sin (nPi/0.3) + sin (nPi/0.3)] as sin(theta) = -sin(-theta)

An = 12/nPi [2sin (nPi/0.3)]

An = 24/nPi sin (nPi/0.3) volts

So taking the 2nd harmonic of this waveform would give

An = (24/2Pi)sin(2Pi/0.3) = 3.31 volts

God, I hope thats right, but please correct me if i'm wrong

Thanks