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So how many sandwiches are there?
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So how many sandwiches are there?
Holy cataclysmic event Batman! He asked a question that Broke the Laws Of Physics!![]()
Sorry your semantics failed![]()
Sorry couldn't help it - your quote belongs somewhere in the Hitch Hikers Guide along the lines of what happens when the Question and Answer appear simultaneaously.
This one:Here we go again....
What point exactly am I missing?
Either the laws of physics apply in which case it'll take off or they don't and it can do whatever the hell anybody cares to think of including turning into a bright pink four hundred storey elephant with a penchant for flip flops.
Please don't start that one!
Yes, it will fly... Please no one else suggest anything else!
What if it didn't have any engines ?![]()
This one:
No, it's 2...![]()
No, it's 2...![]()
The second version of the question stated that the treadmill matches the wheelspeed of the plane. In this case it is impossible for the plane to move. In order for the plane to move the wheels must be moving at a different speed to the treadmill,
LOL I really can't be arsed to get into this but have a word with yourself.
Its got absolutely NOTHING to do with wheel speed.
You could put the plane on skids for all it matters.
IF the engine thrust is greater than the friction of skids/wheels/whatever..
The plane will move through the AIR.
When air speed is greater than the weight of the aircraft due to lift created over the wings.. THE PLANE TAKES OFF.
How can people not see this.. <mind boggle>
That formulation of the question doesn't make sense, so any "answer" to it is invalid.
Assuming the "speeds" of both the conveyor belt (say v) and the wheels (say u) are being measured relative to the ground, then the former will always be twice the latter, i.e. u = 2v. Hence, from the problem statement:
u = v
∴ 2v = v
∴ v = 0
Hence, the only scenario in which the problem statement is mathematically consistent (let alone physically possible) is when the conveyor belt is stationary.