Ok, having skipped over 6 pages of this thread - here's the situation as I see it:
You have a few different senarios here, as follows.
1. You have a plane (757) on a treadmill. The treadmill has constant velocity. With no opposing thrust from the engines, the aircraft will move backwards along with the treadmill, it's wheels not moving. It will continue like that forever.
2. You have a plane on the treadmill, but with it's engines set to produce a small amount of thrust. This thrust is enough to keep the aircraft moving along the treadmill at the same velocity as the treadmill is moving, thus cancelling eachotehr out. To the casual observer, the plane is standing still.
3. The aircraft now has enough thrust to power itself to exactly take-off speed (Vr, or Velocity Rotate) under normal circumstances. It will accelerate to this speed in relation to the conveyor belt, but it's speed relative to the air in which it is moving will be insufficient to allow it to take off. If the conveyor was moving at 30 knots, the aircraft would require a speed of Vr PLUS 30 knots to become airborne.
4. The aircraft has enough thrust to accelerate to Vr+30 knots and beyond. Upon reaching this speed, the aircraft will become airborne.
5. The aircraft has enough thrust to reach takeoff speed, but it's speed is exactly matched by the treadmill instantly. Since the aircraft's only contact with the ground is through the wheels, and these are rotating, they will simply speed up with the treadmill and to the observer the aircraft will again remain stationary. The thrust of the engines is unimportant as this is the only opposite force acting against the conveyor belt. Whatever thrust is being produced will be cancelled out by the belt instantly, and all that will change is the rotational speed of the aircraft's wheels.
The mythbusters video is irrelevant - if you had a plane pulling the conveyor belt with the same acelerative force as the plane ON the belt, the two would simply cancel eachother out.