Eric's collar
Eric's collar
Wrong, in maths, there are only definitions and lemmas.
I was referring to the question. I know x^2=9 has 2 answers but in this case such as 2+2, there is only one answer and that is 5.
Wrong, in maths, there are only definitions and lemmas.
Nope, can't. I've tried. I understand the argument very well and for me it's not the divisor. Trouble is my old Engineers brain will always take the bracketed item as a single term. Using large equations a lot I tend to break them into usable chunks, yeah I can see the other result, but given a choice I see 1 (or dead people).legitimately expand 3(2+1) and you'd arrive at the correct answer![]()
In that case yes, but it hardly applies in generality does it?I was referring to the question. I know x^2=9 has 2 answers but in this case such as 2+2, there is only one answer and that is 5.
I'm not seeing lots of dead people?
Well it was good being part of a very active thread. Now I depart..
2 = 1
Let a = b, then a^2 = b^2.
This means a^2-b^2=0.
Factoring the left yields (a-b)(a+b)=0.
This means (a-b)(a+b)=a^2-b^2.
But since b=a, You can say that a^2-b^2 = a*b-b^2.
Therefore (a-b)(a+b)=a*b-b^2.
Factoring the right yields b*(a-b).
Therefore (a-b)(a+b)=b*(a-b).
Dividing by a-b gives a+b=b.
But since a=b, we have b+b=b, or 2b=b.
Dividing by b gives 2=1.
2 = 1
Let a = b, then a^2 = b^2.
This means a^2-b^2=0.
Factoring the left yields (a-b)(a+b)=0.
This means (a-b)(a+b)=a^2-b^2.
But since b=a, You can say that a^2-b^2 = a*b-b^2.
Therefore (a-b)(a+b)=a*b-b^2.
Factoring the right yields b*(a-b).
Therefore (a-b)(a+b)=b*(a-b).
Dividing by a-b gives a+b=b. <-- And that's where you go wrong.
But since a=b, we have b+b=b, or 2b=b.
Dividing by b gives 2=1.
2 = 1
Let a = b, then a^2 = b^2.
This means a^2-b^2=0.
Factoring the left yields (a-b)(a+b)=0.
This means (a-b)(a+b)=a^2-b^2.
But since b=a, You can say that a^2-b^2 = a*b-b^2.
Therefore (a-b)(a+b)=a*b-b^2.
Factoring the right yields b*(a-b).
Therefore (a-b)(a+b)=b*(a-b).
Dividing by a-b gives a+b=b.
But since a=b, we have b+b=b, or 2b=b.
Dividing by b gives 2=1.
Oh and Hi-Five Dave.
The Unreal Tournament "double kill" voice sprang to mind then![]()
I will say this thread is heading where they all tend to, which is quite a funny observation for me.
PERFECKTHugh - MILLY - ation.
Were you around for the 0.999...=1 thread?![]()
Just a message for some of those who are poking fun at others.
There are two solutions, differing in interpretation of the ambiguous expression.
If you can't understand this then refrain from accusing others of lacking intelligence. Any spastic can apply some Kindergarten mathematical operating rule without really having a grasp on the subject. The argument being put fourth by those who are qualified to debate this is that in practical application of mathematics either interpretation may be more appropriate given the context of the problem at hand, although the expression is still irrefutably ambiguous.