0.99r = 1

RomanNose said:
I swear you only talk about maths, do you have a script running to find maths threads on forums?
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I have a friend who reads this forum and mentions such threads. Usually I just read them and think "Can't be bothered" but when someone says something particularly teeth grinding I'll post. I used to post normally but I rarely read this forum and in general I'm only sitting at my computer if I'm on a science forum or if I'm doing work.
 
Quite enjoyed that! thanks for sharing... And this quite rightly deserves a thread of its own (I would have missed it otherwise)
 
Reaper 392 said:
what about the sum of an infinite series that equals 1, would you say its the same as 1?
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If there is a infinite series in there it can never be whole. Then again pi is infinite but it creates a whole number I'm confused, or does it create another infinite number ?
 
Who really cares...it is only of interest to a Mathematician and as the only actual mathematicians in this thread all agree 0.99r=1 then equals 1 it is.......

And more to the point is 10 a solitary number? and if so, is it lonely?
 
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I really didn't want to post this as I hate being drawn into these types of threads.

For the record: I am not saying that 0.99r does not = 1

What I would like is somebody who is more educated in Mathematics than me to provide the answers/reasons for these as I'm interested. Obviously if my reasoning (as it seems it is before I begin) is off then these are wrong but I'd like to know where.

1 - I watched an example video showing that assuming A = 0.99r then 10A = 9.999, ergo 10A - A = 9.0 (9A). 9A/9 = 1

This stands, I understand it and I'm not arguing against it. However. Assume we do the same equation using 5A instead. Not logically this would be 5A = 4.999r (I guess?), substitute it in the same we still end up with A = 1. Now where this gets fuzzy is that in my head if we multiply (for example) 9.99 x 5 we get 49.95. Now here we have a difference of 0.04. If this was to be a billion longer, the .04 would just move right and the calc would be off

Now as were using an infinite number of 9s after the decimal does this change the way that the fractions of one are added? As at some point even if there is an infinite number of 9s it would mean we would end up with that 5 instead of a 9? I know this is wrong due to the first equation but what happens? Does basic multiplication not apply as we're dealing with an infinite number?

For something to be true it has to hold true with more than one example, how does this example stand up?

2 - Somebody earlier said that if we take 0.99r to NOT be 1 then we must be able to ascertain and write the difference between 1 and 0.99r down. This as I understand it cannot be done as we can't write (from the earlier example) 0.00r1 and even I know this :p

So if we have to find and annotate this difference can't we annotate this numerical difference between 1 and 0.99r using a fraction? i.e. using the assumption 1 = 0.99r then 1 - 0.99r = 0

So on this can't we describe the difference as a valid fraction? Not sure what it would be but in the same way as 0.33r = 1/3?

I know these assumptions are wrong but I want to know where my maths/logic went wrong? Also, yes I am well aware that I am terrible at putting stuff on paper so this probably doesn't make sense :p

Cheers

- GP
 
GhostlyPea said:
2 - Somebody earlier said that if we take 0.99r to NOT be 1 then we must be able to ascertain and write the difference between 1 and 0.99r down. This as I understand it cannot be done as we can't write (from the earlier example) 0.00r1 and even I know this :p

So if we have to find and annotate this difference can't we annotate this numerical difference between 1 and 0.99r using a fraction? i.e. using the assumption 1 = 0.99r then 1 - 0.99r = 0

So on this can't we describe the difference as a valid fraction? Not sure what it would be but in the same way as 0.33r = 1/3?

I know these assumptions are wrong but I want to know where my maths/logic went wrong? Also, yes I am well aware that I am terrible at putting stuff on paper so this probably doesn't make sense :p

Cheers

- GP
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You can define the difference as a fraction if you like, but first you need to quantify the difference. My point being that if the 9s after the decimal dont end where do you put the 1 after the decimal?
 
Sorry. But if you have two numbers

0.9r

and

1

they are different, otherwise you wouldn't need to write them differently in the first place.

If you then have to do a load of calculations to make it equal, then you are doing something wrong.

The basics here are that it's so difficult to tell the difference between the two, you "may as well call them the same".

Exactly the same way you would 1/3 (one third) equals 0.3r

It makes it convenient, it doesn't make it the same.

(I do not have a maths degree).
 
Scougar said:
The basics here are that it's so difficult to tell the difference between the two, you "may as well call them the same".

(I do not have a maths degree)
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No. The basics are there is no difference so they are the same.

(I have a physics degree)
 
dowie said:
0.3r is just the decimal representation of 1/3
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(disclaimer: my highest maths qualification is a GCSE B)

I simply cannot understand how 0.99r can equal 1.

By that logic 0.33r would equal 0.4.

You can represent 1/3 as a decimal 0.33r, but that is a fraction. 1 is an integer, the decimal representation of 1 as a decimal is 1.0, not 0.99r.

That's my take on the subject

*Head explodes*
 
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