the X is 'execute' pressed at the end of every attempt
the C is cancel and start again
the Y can be included in the 'code'
any code is meaningless, its just an arrangement of ones and zeros.
so the combination is
1234567890Y = each set to 0 or 1
00000000000
<snip> every combination of those inbetween
11111111111
= 11 bits, so 1024?
It's unlikely to are allowed nothing as the code
![Smile :) :)](/styles/default/xenforo/vbSmilies/Normal/smile.gif)
so 1023, much less if the code is fixed to 4 digits, that would be:
11 x 10 x 9 x 8 ? = 7920
1 in 11
2 in 10
3 in 9
4 in 8
ok thats wrong
lol stream of conscienesnss safe cracking
the chances of me guessing the first correct one is for a 4 length code
there is a row of 1s set, so eg the code was set like this:
1234567890Y
10010011000 = my 'code' is 1478 and its also 4187 etc
this is the failure of such a lock,
I have a 4 in 11 chance of guessing the correct code digit, every time I press a button. nuts.
That's not 40% as its 4 out of 11 so its slightly less than 40% less, erm how does maths work again. need coffee.
so its like 36% * length of code (4 digits vs 5 etc)