12 DC to 240AC system draw help!

Err no, it means you can draw 40W at 240V assuming your inverter has 100% efficiency.

/edit Watt is a measure of power. The maximum you will get out of the system is what you put into it, in this case 40W
 
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As Fourstar says above you'll only ever get 40W out of it. At 240V this equates to 0.16A.

(40W / 240A = 0.17A)

Not a lot!
 
I think i may include a deep cycle battery , does that mean I can draw what ever wattage I want off the deep cycle ? ( althought it may decrease the amount of time the battery is charged )

EDIT: will a battery with higher a AH last longer ?
 
I assume you have a panel connected to a battery, correct?

You can draw any amount of power you wish from the charged battery assuming that it is capable of providing the required current. Whether or not a larger amp hour battery will last longer depends on whether your current battery is able to store all the power from the panel. You can however not draw more than 40W of power from the panel itself, so if the battery is not charged you're limited to 40W max.
 
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Having batteries may or may not help depending on the load you wish to power, how long you wish to power it, how frequently you wish to power it and how much you want to spend.

My parents have a beach hut in which they use solar.

There is a 100W panel charging two 150Ah batteries through a charge controller. This powers 50W 12V halogen lights, a 250W inverter, water pump for the tap and fan in a caravan style gas heater.

They don't bother with deep cycle/superior quality batteries any more as they found the cost premium wasn't worth it based on their usage over the years.

As an example lets say:

1) Your solar panel provides its full 40W for 8 hours a day. At a guess possible in the height of summer but not for the rest of the year.
2) The system efficiency of the battery and charging controller is 60% (source)
3) Your inverter is 90% efficient (source)

The panel delivers 40W * 8 hours = 320 Watt hours per day
320Wh * 60% efficiency = 192Wh available to your inverter
192Wh * 90% efficiency = 173Wh available to whatever you are powering.

173Wh / 300W = 0.68 hours or 35 minutes.

According to these figures your solar panel could power your 300W load for 35 minutes a day.

If you only wanted to use it once per week and had big enough batteries you could charge for 6 days then get 3.5 hours use on the 7th.

These efficiency figures may or may not be realistic and I have no idea what fraction of its peak power a solar panel produces over an average day. I just pulled some figures out of google searches.

To put it another way your 300W load is 7.5 times larger than your 40W supply (300/40=7.5). This means you need to supply 40W for 7.5 hours to power your 300W device for 1 hour. This is before taking into account any of the losses I listed above.
 
lol, just seen you're doing a GCSE question not wanting to run something for real.

You may not want to include my efficiency figures as the green police may drag you off to their correctional facility for re-education. Solar and Wind cannot be questioned!
 
Having batteries may or may not help depending on the load you wish to power, how long you wish to power it, how frequently you wish to power it and how much you want to spend.

My parents have a beach hut in which they use solar.

There is a 100W panel charging two 150Ah batteries through a charge controller. This powers 50W 12V halogen lights, a 250W inverter, water pump for the tap and fan in a caravan style gas heater.

They don't bother with deep cycle/superior quality batteries any more as they found the cost premium wasn't worth it based on their usage over the years.

As an example lets say:

1) Your solar panel provides its full 40W for 8 hours a day. At a guess possible in the height of summer but not for the rest of the year.
2) The system efficiency of the battery and charging controller is 60% (source)
3) Your inverter is 90% efficient (source)

The panel delivers 40W * 8 hours = 320 Watt hours per day
320Wh * 60% efficiency = 192Wh available to your inverter
192Wh * 90% efficiency = 173Wh available to whatever you are powering.

173Wh / 300W = 0.68 hours or 35 minutes.

According to these figures your solar panel could power your 300W load for 35 minutes a day.

If you only wanted to use it once per week and had big enough batteries you could charge for 6 days then get 3.5 hours use on the 7th.

These efficiency figures may or may not be realistic and I have no idea what fraction of its peak power a solar panel produces over an average day. I just pulled some figures out of google searches.

To put it another way your 300W load is 7.5 times larger than your 40W supply (300/40=7.5). This means you need to supply 40W for 7.5 hours to power your 300W device for 1 hour. This is before taking into account any of the losses I listed above.

thank you very very helpful !
 
lol, just seen you're doing a GCSE question not wanting to run something for real.

You may not want to include my efficiency figures as the green police may drag you off to their correctional facility for re-education. Solar and Wind cannot be questioned!

this is not anything to do with GCSE's im planning on getting the panels when I get this months pay
 
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