A little help with some binary please...

[Leeum]

Hi,

Doing some binary multipication and I'm a little stuck.

My working is as follows:

The problem comes when adding it all up. I understand that for adding four 1's, it equals 0 carry 2. When I come to add up the next set of digits, I have three 1's and 2 already being carried. What happens then?

Any help appreciated.

 

[Leeum]

Ahhh, that's where I've been going wrong! Managed to get the right answer now - many thanks.

 

[Leeum]

You certainly were. Surely my gratitude is prize enough?

Haircut/ Poweredge... any chance I could add you to MSN? Just started my CS degree and maths isn't my strong point... especially when it's taught by a ukrainian lecturer.

 

[Leeum]

Which uni you at?

Newcastle bud - I'm a home student though (boo hoo)

 

[Leeum]

Not on MSN here, but I'll PM my mail addie so you can give me a shout if you need a hand with compsci-type-stuff. Been paid to p*ss around with software for well over 20 years now, so if I don't know, I usually know someone who does.

Thank you kindly.

You might have a job PMing me, hehe. My e-mail is in my trust though!