Anyone good at ciphers?

[penski]

Give this a shot:

)?8"633'#4¿9("*_@?"(9?"*#438±?*?/q

*n

 

[penski]

I'm guessing " is a space, and ) is a t.

Wrong on both accounts.

*n

 

[penski]

Do you know the plaintext? Any clue as to context? Given that it's such a short sample it's going to be incredibly hard to decrypt

Have a longer one then:

918_9¿3')?8"63_8,3_9#4¿+/?_#?"*#438±#[4_*¿?*?\=3*?,34_*¿+#?838;4)?83'_,;_8/289_/_#4(8'7_;6@_/:"0



*n

 

[penski]

Oh and as for context, both are about me and both include penski at some point.

*n

 

[penski]

Right, seeing as the more text you have, the better...have a song:

"(9¿"_1#4¿?8,3'8?_/
"(9¿"_1@?=="?¿_/9_+?:8"((8
@?==3;?/#_38=14()¿@¿@3==
3"2/¿;(2=,2"¿+*_;_#3(8-/(9#43"
72=="$3*#4/?¿/38+
;3/;2""3:?"4(@
(_-/?_6'4?/¿38#43'4()?=?"'-2;638±4(=¿@?;_===_
#4¿(8=1@_1#[-3-3*3'#[-=2"43*_==_@_1
_81-2;638±#39?
_81-2;638±:_1
=?_/8#["@393=="?¿1(2@838_/3'(8+7_1

-/?*-(¿1(2\-3+2/¿_8:
-/?*-(\1(2\=_##?_8:
-/?*-(\1(2\=_@"23*_8:
-/?*-(\1(2\4_3/)3?;¿_8:
-/?*-(\1(2\)/('_._8:
-/?*-(\1(2\)3=(*_8:
-/?*-(\1(2\;(8#/_;*_8:
-/?*-(\1(2\;_/

3#'+72=="43*#4/?¿/38+
;3/;2'"3:?"4(@
(_-/?_6'4?/¿38#434()?=?"'-2;638±4(=¿#4?1;_===_
#4¿(8=1@_1#[-3-3*3'#[-=2"43*_==_@_1
_81-2;638±#39?
_81-2;638±:_1
=?_/8#["@393=="?¿1(2@838_/3'(8+7_1

"(9¿"_1+;(9?*@3==-_==-/(9#4¿"61
-(==(@?,719?#?(\"4(@?/'_8,#3:+@_*?"
-(==(@?,71-_2=*=38?'#4_*;_88(*"3*"#3==
-(==(@?,7193==3(8'(_:297-(28:?,:3)"43#"
"(9¿"_1#4¿?8,3'8?_/
"(9¿"_1@?=="?¿_/9_+?:8"((8
@?==3;?/#_38=14()¿@¿@3==

That better? got bored halfway through...

*n

 

[penski]

...Damn you got my hooked figuring it...

is )?8"63 Penski at any chance?

Rich

Yup.

)?8"63_#+9_3=#;(9

#4_*3'91?9_3=_::/?""

*n

 

[penski]

Is a Space a character or do we figure those out ourselves?

Rich

if the preceeding character is a number, 'space' does not appear.

if the preceeding character is not a number, then 'space' causes the preceeding character to change to the next character on a predetermined string. The string is a cyclic list of the same 'type' of character.

For example, you know that )?8"63 is penski.

the standard character for p is )

the cyclic string for ) is as follows:

p = )
p, space = ]
p, space, space = }
p, space, space, space = >
p, space, space, space, space = »
p, space, space, space, space, space = )

...and it will continue to cycle in that manner.

The only exception to this rule is the letter L which does not appear as a number and is not modified by 'space'...

*n