Array length in C++?

[Auraomega]

Not something I've ever had to do before (shockingly), maybe I'm just being dim but shouldn't:

void c_maze::blankCellsList(s_blanks *list)
{
	int listSize = sizeof(list) / sizeof(s_blanks);

Work?

 

[NickK]

No. For a variety of reasons:

sizeof(list) will return the size of the pointer and not the size of the block it's pointing at.

It's also bad to assume there's no compiler padding etc by doing pointer arithmetic unless it's byte aligned. If the type changes then you code breaks.

 

[Auraomega]

Fair enough, should I just go down the vector route and call size to do it for me?

 

[NickK]

That is one option.

Usually, unless you're designing for supercomputer high performance or embedded system efficiency, then you'll not need to stray away from the standard libraries.

 

[Auraomega]

I was just trying to avoid vectors to keep the library portable to C, but when I think about it C has very limited use these days anyway. Vectors it is!

 

[steve-h]

but when I think about it C has very limited use these days anyway.

what?!?!?

wash your mouth out with soap

 

[zpos]

I was just trying to avoid vectors to keep the library portable to C, but when I think about it C has very limited use these days anyway. Vectors it is!

lmao!

 

[Auraomega]

I meant as in most people use C++ over C, stop picking on me