Equation Rearranging Help

divine`

divine`

divine`

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Southampton University
Trying to follow through a bit of working and i've got a bit stumped where the jumps have been quite big...

Would someone mind explaining how the rearranging gets the following equations?

equationhelp.jpg


I think I just about get the first step, the second to third is where i'm where really confused!

Cheers :)
 
Ok to get from 2 to 3,

multiply 0.849, PI/4 and 1/(4^0.63) together to give 0.278 (3dp)

So we now have Q/CD^2.63=0.278*(hf/L)^0.54

Then take the 0.54th root of eveything, ie increas everything to the power of 1/0.54 which is 1.85.

This gives (Q/CD^2.63)^1.85 = 0.0939*(hf/L)

Then multiply by L and divide by 0.0939 to get the answer hf=10.21*L*(Q/CD^2.63)^1.85
 
The last step must be subbing in values for L, C and D.

ALso allow for rounding errors in the values above, they may not be exact as given in your OP
 
OSB said:
no worries, random values though, whats it for?
Click to expand...

It's the Hazen Williams Formula, for hydraulics, using it to calculate head loss due to friction so I can then calculate flow... There's a pump thrown in there too, just to complicate it a bit :p
 
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