Further Maths help

Soldato
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29 Jun 2006
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Sheffield
I'm not sure who has got this answer right, me or my textbook (it wouldn't be the first time it gets something wrong).

This is imaginary numbers btw, i = square root of -1.

Q10. Given that z = -1 + 3i, express z + 2/z in the form a + ib, where a,b € R (a and b belong to the set of real numbers).

This is what I did:

z + 2/z

(-1 + 3i) + 2/(-1 + 3i)

(-1 + 3i) (-1 + 3i) + 2

Expand the brackets: 1 - 6i + 9(i squared)

1 - 6i - 9 -> -8 - 6i

-8 - 6i + 2 -> -6 - 6i

The book's answer is: -6/5 (1 - 2i)

Have I just made some retarded mistake or is their answer wrong?
 
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