GCSE Maths Question

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I'm stuck with finding equations from exponential graphs. I can do quadratics - no problem. But these just seem a lot harder.

There is an example of how to find quadratic equations from graphs in the CGP revision guide, but not exponentials. The "Acid Test" question asks you: "The graph shown here is thought to be represented by the equation Y = PQ^x where P and Q are unknown constants. Use the graph to find the values of P and Q".

Since you don't have a copy of the graph, I'll give you the two points I found on it: (0, 50) and (2, 100). In the method they say you need two points, preferably on either the X-axis or Y-axis, only one is.

Could someone give me a walkthrough of how to do it and questions like this?

TIA, Etaqua. :)
 
It's not homework, it's a page in the CGP revision guide. :p

Edit: I already have the answers, they're in the back of the book, but I don't know how to do this type of question.

Q = 1.41 and P = 50, if you need proof I'm not cheating on some homework. :p
 
Mmm, I don't think we do logs at GCSE stage, so I don't think that's how we're supposed to do it. There is no mention of them on the page which (doesn't) explains how to solve them.
 
If you want to add me to msn, I can see if my brain remembers back 12 months, I may be able to help.

:)

sag-okia at zen.co uk
 
It's quite easy - just stick in x=0, and you find P trivially, then stick in the other point!

explicity:

consider y=PQ^x @ (0,50)

=>50 = P

.:
100 = 50Q^2 (considering (x,y) = (2,100))
=>2 = Q^2

.: Q = +/- sqrt(2)
 
Last edited:
Amleto, you are a lifesaver. You also reminded me that x^0 is not 0, but 1. I think that's where I went wrong...

Thanks @ Amleto.

*hands Amleto a beer and young woman*
 
iirc, theres RULES about posting homework questions on these here forums, so you godda ask your self..........do I feel lucky?


well? do you punk?
 
VeNT said:
iirc, theres RULES about posting homework questions on these here forums, so you godda ask your self..........do I feel lucky?


well? do you punk?


EASTWOOD.jpg
 
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