GCSE maths question

Similarly to how you did it but remember that i is a constant value not a variable. Try seeing it as (x + (i - 2)) instead of ((x + i) - 2).

And read the question properly. He wants the quadratic solving against a line (specifically the x values of the two intersections). Do your multiplying out and get everything on one side, then set that equal to the equation for the line (given later in the question). Rearrange, multiply, add, whatever to get it as a quadratic so you can then use the quadratic formula.
 
Diddums said:
I missed Touch's answer, and I haven't got the results back yet. I'm just trying to see what the outcome will be as this one had me scratching my head for bloody ages :D


I've got a beer riding on this too!
Click to expand...

This was due in on the 1st of March, i got my results back on the 6th!
 
Tuppy_Glossop said:
Similarly to how you did it but remember that i is a constant value not a variable. Try seeing it as (x + (i - 2)) instead of ((x + i) - 2).

And read the question properly. He wants the quadratic solving against a line (specifically the x values of the two intersections). Do your multiplying out and get everything on one side, then set that equal to the equation for the line (given later in the question). Rearrange, multiply, add, whatever to get it as a quadratic so you can then use the quadratic formula.
Click to expand...

spot on

But i did (x+i-2) rather than (x + (i-2)).

Was really tough to make it a non complex answer, so i cheated and used another line to equal the quadratic so that the answer was not complex. Although the lack of replies makes me feel that i probably went wrong somewhere and the answer doesn't cancel out to something simple as i tried to make it.
 
My answer:

(i say my answer because you made me lose confidence in trying to make a complex quadratic with a integer answer)

(x + i -2)^2 = i(2x - 4)

Expand brackets

x^2 + 2xi - 4x + i^2 - 4i + 4 = 2xi - 4i

Cancel bold stuff out + i^2 becomes -1

x^2 - 4x + 3 = 0

(x-3)(x-1)

x=3
or
x=1
 
Not sure if this link will work!

20160318_155829.jpg

Holy image size batman!
 
I'm trying to attempt to explain the original questions to the OP. Sorry if it comes across as I'm treating you like a dumb dumb, but I felt it was best to go back some ways. That said, it assumes basic algebra, including but not limited to equation transposition.

Also, image sizes are large.

Also also, I apologise for the hole at the bottom of pages two and three. I spilt rum.

p82km.jpg

28u34g6.jpg

294qf0j.jpg

Check that out for dissertation procrastination! :D
 
You guys want another headscratcher?

This one had me going for a bit. It's quite simple when you suss it out but it took me bloody ages to get them right :D

ZTztcma.png
 
a)
t(5+4k) = 9s
5t + 4tk = 9s
5 + 4k = 9s/t
4k = (9s/t) - 5
k = ((9s/t)-5))/4

b)
9k-7t = 15sk + 12st
9k - 15sk = 12st + 7t
k(9-15s) = 12st + 7t
k = (12st + 7t)/(9-15s)
you can alter that some more but k is the subject.
 
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