Geometrical symmetry question - mirror symmetry in triangles

ntg

ntg

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24 Nov 2008
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Right, i've been reading about how M*R =/= R*M but I can't get my head round it.

On one hand it has an isosceles triangle (i know in the post it comes off like a 90 degree triangle but I can't fix that) which is mirrored and then rotated, so from:

A

B C

it is mirrored and stays the same, then rotated and becomes:

B

C A

Fair enough, but then when it's rotated and mirrored the book says the following happens:

rotated

B

C A

mirrored

B


A C


I can't get why in the mirroring at the end the CA changes to AC, whereas in the first case it doesn't.

anyone can explain it to me? I'm not sure I understand mirroring in the same way the book describes it.
 
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