Help! quick maths help needed

Caporegime
Joined
20 Jan 2005
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Location
Co Durham
My brain is failing me today and I quickly need the answer to the following.

In the next 18 months there are 7 months of importance. I know for sure that 4 other important things will occur in the next 18 months.

What is the probability that one of the 4 things coincide with one of the 7 months of importance.

Needs a quick answer, help please. Greatly appreciated.
 
Just to clarify as I may not have explained it properly.

There will be 7 important months in the next 18. This is a 100% certainty. The only thing not known is which 7.

There will also be 4 other different important events cropping up in the next 18 months. This is also 100% certainty.

Therefore I am trying to find out what the chance is that any one of the 7 important months coincides with one of the 4 important events.

It does not matter if more than one occurs eg all 4 coincide or just 3 or 2. Just need to know if at least one does.

Gut feeling is that multiplying is wrong as the answer is too low.....
 
Ye gads.

It's easier to work out the probability of it not occurring - which is (11/18) to the power 4 - and subtracting that from 1.

So your probability of one or more conflicts is 86%

That's looking favourite so far and makes sense. ANy more confimations that this is the right answer please?
 
Oh, also, does it matter if any of the 4 other important things coincide with each other?

That would make it 1-(11/18)(10/18)(9/18)(8/18) = 92%

Yes it does. Never thought of that. None of the 4 events can occur in the same month.
 
Let's look at a similar problem. Suppose you have two coins and you flip them, what's the probability that they will both be heads?

I think it's the same type of problem. You got 1/2 chance of the first coin coming out heads (i.e. 7/18 months) and again 1/2 chance of the second one (i.e. 4/18). To find the answer you need to multiply. I stand by my answer which comes at around 8.6%.

No. It's more like the old problem of what are the odds if you have 30 people in a room together that two people have exactly the same birthday. Most people work it out to be really low. The actual answer is near enough 50% which surprises most people.

(this assumes that every day is just as likely to be somebodies birthday which in real life isn't true is AUgust/September has the highest birthrates - xmas and new year "accidents" plus major power cuts cause peaks as well ;))
 
Ye gads.

It's easier to work out the probability of it not occurring - which is (11/18) to the power 4 - and subtracting that from 1.

So your probability of one or more conflicts is 86%

Thinking about it because none of the 4 events can occur in the same month, shouldn't it be

1- (11/18 * 10/17 * 9/16 * 8/15) ?

as once you have the probability that the first event didn't coincide you only have 10 months of the 17 months left for the 2nd event to occur in.

Or am I over analysing this?
 
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