Help with BASH command to variable

[Dirk Diggler]

Been throwing everything at this, but just can't get it to play nice. I'm trying to extract info from an api.

If I have :

echo "$jsonTxt" | jq '.[0].algo' | sed "s/\"//g"

It outputs :

x15

That output is perfect, it's the first algo returned. I want that "x15" into a variable so I can use it later in the script, so I'm trying :

outputTxt=$("$jsonTxt" | jq '.[0].algo' | sed "s/\"//g")
echo "$outputTxt"

But it errors, saying :

line 16: "[{"algo":"x15","score":"0.00443727"},{"algo":"x13","score":"0.0031609"},{"algo":"x11","score":"0.00192839"},{"algo":"nscrypt","score":"0.0014518"},{"algo":"scrypt","score":"0.000689165"},{"algo":"nist5","score":"0"}]": command not found

 

[Evilpaul]

echo "$jsonTxt" | jq '.[0].algo' | sed "s/\"//g"

The first command here is to print the contents of $jsonTxt using echo, this is then piped into the following commands.

outputTxt=$("$jsonTxt" | jq '.[0].algo' | sed "s/\"//g")
echo "$outputTxt"

Here you are not printing the contents of $jsonTxt, but rather trying to run the contents as a command.

 

[ChrisB]

Here you are not printing the contents of $jsonTxt, but rather trying to run the contents as a command.

Quite fittingly, he's trying to execute himself

 

[Dirk Diggler]

Yea, thanks for the help guys.

Anyway, I've managed to sort it.