Help with Binomial Maths? xD

[Cookeh]

Anyone one able to work out the following binomial distribution question? Its had me stumped for ages

"Some eggs sold in a store are packed in boxes of 10. For any egg, the probability that it is is cracked is 0.05, independently of all other eggs. Calculate the expected number of cracked eggs in a box."

I got as far as C~B(10, 0.05) where C = cracked eggs. But stumped from there

Please dont spam saying Im dense or anything similar

Thanks in advance,
Cookeh

 

[Cookeh]

Taken literally the answer is 10, since the question doesn't ask for the expected number of uncracked eggs in a box.

Sorreh! I really am dense xD
Fixed for correctness

 

[Cookeh]

Never heard of binomunal maths, so guess this is "probably" wrong, the probability of a cracked egg is 5% which would be easy if there were 20 eggs in a basket (1 egg cracked)

So number of eggs cracked = 1/2 of an egg

That's about as far as I can get yer buddy.

I arrived there.
But not 100% sure of it.
And its A2 level stuff, think its fairly new to the syllabus?

 

[Cookeh]

I did binomial maths in my A-Level maths. That was ages ago though, I do remember it was pretty easy to me (but Stats was my best area of maths by far). However, this has been entirely unhelpful to you, apologies!

lol, no problem at all xD
This is oddly the only thing I have yet to struggle with at maths /:

Finding the expectation when dealing with the binomial distribution simply involves multiplying the number of things by the probability

E(X) = np = 10*0.05 = 0.5

Awesome, thanks. Didnt think it would be that easy

 

[Cookeh]

See, told you Stats is easy.

Can I ask you guys another question on it then? xD