Shame that you don't have the intellectual capacity to even understand the thread title let alone the question.Oh.
I thought you wanted help distributung poison. Im out then.
I understand it very well. I know what it all means, I just don't know how solve it.Yeah... Imagine not having the intellectual capacity to understand the question...
Hold up...
Yeh thats right.. Thanks for the helpI have a solution and I hope it is right, lol.
X~Poi(n)
Given that the PMF of the Poisson dist is P(X = k) = (e^-n * n^k)/k! we can form a polynomial:
(e^-n * n^5)/5! = (e^-n * n^4)/4! + (e^-n * n^3)/3!
Multiply by 5!/e^-n to get:
n^5 - 5n^4 - 20n^3 = 0
Factorise
n^3(n^2 -5n - 20) = 0
Use quadratic formula and u get solutions
n = 0 (thrice), 7.623475 and a negative value.
The poisson dist has the requirement that the parameter, n > 0, so I would take n = 7.623475 as the solution (assuming I didn't make any silly mistakes).
Sufficient revision early enough for what? I don't have exams until June. I'm not taking A level.Getting shirty because you failed to do sufficient revision early enough![]()
Because I'm learning it in Higher Maths for my IB Diploma.Why do you need to know this then?
Are you seriously doing poisson distribution at GCSE?
Or maybe you're in the maths club![]()