How to insert an IF statement

[Minibiker]

Hi all

I'm currently doing a beginners project on Python and got to a hurdle now, I need to insert an IF statement, I need a little help if anyone on here has experience in this please

Basically I want it to say "is there anything else I can help you with?"

This is where I keep getting an error, I want it to have a yes and no answer but not sure how to get them in. So if the user answers yes print what I put in and if they answer no then print another statement

Any help appreciated

 

[Begbie]

You'll need an elif, or a else if. My knowledge is a bit poor though. I'm sure someone else will be along to help more.

 

[Zefan]

Pretty sure with just two conditions a standard if else is all that's required, this should be a simple google job and paste in your condition.

 

[Temujin]

There's a lot of ways to deal with this really, to get the yes or not answer you should prompt the user for an input initially which iirc can be done in Python by

input("Is there anything else I can help you with?")

However you want to save the response by the user so you can test it later to see if it's what you expected, this can be done using a variable and the assignment operator and then you can test its value in the IF statement.

This inherently will only run once, since the code will be executed line by line, so you may want to not let the user progress until they have given a response you expect, so a form of input validation. This can easily be achieved by using a loop, which tests the value the user inputs and if not as expected will restart the loop again. You could save the acceptable answers in an array, which a conditional (if) statement could check on each iteration of the loop to see if the response should be accepted

I get this is probably over complicating your request a bit, but it's the ex-tutor in me. I'll put a solution in a spoiler so you can have a look at what I mean, or try solve yourself

Spoiler: solution

help = ""
answers = ['y','n']
while(True):
    help = input("Is there anything else I can help you with? (y/n): ")
    if(help not in answers):
        continue
    else:
        break

An explanation of the above:

• Create an initialised global variable help where we can save the response
• Add some acceptable responses to an array so we can test input (could also add 'yes','no' or whatever)
• use an endless while loop (sort of dangerous as this will run forever unless we break somewhere)
• Get input from the user, save to the previously made variable
• test the value returned by the user in an if/else conditional statement
• if the entered value does not exist in the array, we continue (jump back to the top of the loop, re-ask the question) ((would probably be better to print an error, pointing to acceptable answers before asking again))
• If it does exist (yay) then we break out of the while loop and the program finishes

 

[Minibiker]

There's a lot of ways to deal with this really, to get the yes or not answer you should prompt the user for an input initially which iirc can be done in Python by

input("Is there anything else I can help you with?")

However you want to save the response by the user so you can test it later to see if it's what you expected, this can be done using a variable and the assignment operator and then you can test its value in the IF statement.

This inherently will only run once, since the code will be executed line by line, so you may want to not let the user progress until they have given a response you expect, so a form of input validation. This can easily be achieved by using a loop, which tests the value the user inputs and if not as expected will restart the loop again. You could save the acceptable answers in an array, which a conditional (if) statement could check on each iteration of the loop to see if the response should be accepted

I get this is probably over complicating your request a bit, but it's the ex-tutor in me. I'll put a solution in a spoiler so you can have a look at what I mean, or try solve yourself

Spoiler: solution

help = ""
answers = ['y','n']
while(True):
    help = input("Is there anything else I can help you with? (y/n): ")
    if(help not in answers):
        continue
    else:
        break

An explanation of the above:

• Create an initialised global variable help where we can save the response
• Add some acceptable responses to an array so we can test input (could also add 'yes','no' or whatever)
• use an endless while loop (sort of dangerous as this will run forever unless we break somewhere)
• Get input from the user, save to the previously made variable
• test the value returned by the user in an if/else conditional statement
• if the entered value does not exist in the array, we continue (jump back to the top of the loop, re-ask the question) ((would probably be better to print an error, pointing to acceptable answers before asking again))
• If it does exist (yay) then we break out of the while loop and the program finishes

Thank you for the detailed answer, much appreciated