Hyperloop acceleration
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Soldato
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Fag packet no calculator about 6 seconds I think.
I got the acceleration assuming equal acceleration and deceleration as about 4.5m/s^2
An online tool tells me 4.5m/s^2 is abut 0-60 in 6 seconds
edit: willing to accept I'm wrong if anyone disagrees.
I got the acceleration assuming equal acceleration and deceleration as about 4.5m/s^2
An online tool tells me 4.5m/s^2 is abut 0-60 in 6 seconds
edit: willing to accept I'm wrong if anyone disagrees.
If the hyperloop went from 0 to 107 miles an hour and back to 0 again in 500 metres, what would be the acceleration rate, 0-60 time?
Can someone work it out?
Presumably it envoles s =ut +1/2 at squared??
There's not enough information to calculate it, unless you make assumptions such as the acceleration and deceleration being constant and the same which is highly unlikely.
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They could be though, it'll give a rough idea.
Well if we assume s = 250m.
v^2 = 2as rearranges to a = (v^2) / 2s therefore a = 4.52ms/^2
26.7m/s (60mph) / 4.52 is 5.9 seconds.
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Soldato
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I agree, much more likely a higher initial acceleration and longer coast stage. My calculation is effectively the minimum acceleration you could achieve it with but no the most likely.
Obviously a few assumptions required but my rough working:
107mph = 47.833 m/s
Assuming linear acceleration the average speed would be half of this (23.92m/s)
Assuming rates of acceleration and deceleration are equal you’d be accelerating over the first 250m. Covering 250m at an average speed of 23.92m/s would take 10.45 seconds
Accelerating from zero to 23.93m/s over 10.45 seconds with constant acceleration would require a rate of 2.28m/s^2
2.28m/s^2 would equate to about 0.23g which doesn’t sound particularly uncomfortable
107mph = 47.833 m/s
Assuming linear acceleration the average speed would be half of this (23.92m/s)
Assuming rates of acceleration and deceleration are equal you’d be accelerating over the first 250m. Covering 250m at an average speed of 23.92m/s would take 10.45 seconds
Accelerating from zero to 23.93m/s over 10.45 seconds with constant acceleration would require a rate of 2.28m/s^2
2.28m/s^2 would equate to about 0.23g which doesn’t sound particularly uncomfortable
Similar to kaiowas calculation above, you could do it with an acceleration equivalent to around a car doing a 6 second 0-60 time, and then braking at a similar rate that the highway code assumes for a passenger car (albeit extrapolated up to 107mph as the higway code doesn't suggest stopping distances for that speed!)
Of course, it could be faster acceleration with a coast, but that's the min performance required
Of course, it could be faster acceleration with a coast, but that's the min performance required
As others have said a question with way too many variables to even be able to assume a value. did it reach 107mph within 50m then travel at said speed until 400m before it started decelerating? There just isn't enough information to make an educated assumptive guess.
Soldato
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Surely that should be 47.83m/s not 23.93m/s otherwise agree with your method.
Soldato
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You’re right, I’d noticed I’d come up with a different answer to you by a factor of 2 and my answer instinctively felt like it was too low but I couldn’t see what I’d done wrong
Caporegime
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Good ol' atmospheric pressure, the amount of energy it can release and exert as force is mental.
Have a look at this video to have an idea of what could happen in the event of a sudden decompression:
As for the Hyperloop, this is in the same category as flying cars, quantum computing and fusion: always 30 years away. I'll believe it when I see it.
Not sure but road going vaccum tankers have strengthening ribs to help prevent that happening.
Soldato
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1 bar differential pressure even on a large tube isn't that hard to overcome. Submarines routinely manage 20 bar diff pressure and are designed for much more.
What conventional motorbike is doing 400mph?!