IP Addressing Scheme - Would This Work?

Stellios

Stellios

Stellios

Soldato
Joined
27 Aug 2004
Posts
17,111
Location
Geordieland
Hi guys, could do with some input here. Ive got a networks resit to do for uni, and ive spent the last week trying to get my head around VLSM and IP Addressing etc etc and could just do with some advisement as to whether this IP scheme would actually work as I dont have access to a the network room at uni to test it out.

I really need to get this bit right, as afer this I need to extend on the network, which is my reasoning for asking for advisement here before proceding.

Base IP given by lecturer is 160.32.84.0 /22

ipscheme-1.jpg


Below is my working out method, not sure if anyone will understand my workings, but here it is anyways just incase you do

networkplan.jpg


Thanks you for any advice given, it really is hugely appreciated
 
Last edited:
As it stands, no...

I'm not sure where you're getting the 160.21.8x.0 addresses if your base address is 160.32.84.0/22 (the usable range for your base address is 160.32.84.1>160.32.87.254)

the first split is probably a /23 then the rest of your sums look about right...

Kev
 
That makes sense now you have said it, ive started at 84 and worked backwards instead of forwards, im an idiot :o

As for the /23 you are correct now ive checked my notes, it just me being stupid again.

Got closer than I did last time, my last attempt resulted in failing the module I cocked it up that much.

Thank you very much for your time mate
 
It's not that bad (you were pretty close!)

Subnetting isn't easy - it also depends on the method too. The guy at work whose doing his CCNA has quite a good method (which I can't remember!) but it seemed better than when I did mine.
As it stands, I'm rubbish at maths and subnetting -I cheated and used a calculator ;) Thankfully the CCNP didn't require as much as the CCNA, but you start to learn what looks right and what doesn't.

Always remember to work forward from the base address :) Additionally write the mask out ie 255.255.252.0 = /22 ignore the 255.255 bit (the first two octets of the IP) as you can't change these bits and then you've got the rest to play with :)
 
Right, if you dont mind mate will you check over this revised one.

To be honest its took me quite a while to get my head around VLSM etc, I thought I was good at networking, and oh how this module has proven me wrong.

EDIT - Ive spotted the IP typo on the second IP down

ipscheme.jpg


networkplan-1.jpg
 
Last edited:
Chief Wiggum said:
Subnetting isn't easy - it also depends on the method too. The guy at work whose doing his CCNA has quite a good method (which I can't remember!) but it seemed better than when I did mine.
As it stands, I'm rubbish at maths and subnetting -I cheated and used a calculator ;)
Click to expand...


Ive sort of cheated, to get the subnets as i got linked to THIS page, which I have used a lot, as it shows you the split point between host and network parts which make it easier for calculation
 
No problem!

It looks fine to me - the only thing on your working out is that you're carrying the broadcast of the last subnet down instead of the network address of the next subnet.

The only other thing is do you have to account for any expansion? as you're left with 160.32.87.0/24 for future use.
 
Yep, the next part I need to do is the addition of more subnets equating to around about another 220 hosts, which is where the spare address comes in :) This is the reason I was asking for advisement on this part, as if I ballsed this part up it would muck up another part of my work.

I really cant thank you enough mate for your time, youve saved me an awful lot of time and headache
 
Last edited:
ah! that explains that then!

anytime :), anyone who has been there before knows what it's like, so I'm more than happy to help :)
(wouldn't be where I am now if people didn't help each other out!)
 
You must log in or register to reply here.
Back
Top Bottom