Limits

[ugatennis08]

Hey,

I just had my test and was wondering if I got the right answer for this question:


lim x->3

[(1/x)-(1/3)] / x-3

is the answer Does not exist?

 

[Dave]

is the answer Does not exist?

TI-83 says no Should approach -1/9 I think from looking at the TI?

(assuming you mean the function f(x) = [(1/x)-(1/3)] / (x-3) )

 

[SoSolid]

Aint it 0/0?

 

[Azagoth]

42

 

[Neoni]

42

Lol

 

[daz]

It goes to 0/0 at the limit, so i'm pretty sure it's not defined/doesnt exist.

Edit: L'hopitals rule says otherwise.

 

[Inazuma]

Wait.. you divided by zero?

 

[Cold_And_Miserable]

It goes to -1/9. Since it can be simplified to -1/3x

 

[DaveF]

Hey,

I just had my test and was wondering if I got the right answer for this question:


lim x->3

[(1/x)-(1/3)] / x-3

is the answer Does not exist?

Nope. If you know the limit definition of the derivative, you should be able to recognize that limit as the derivative of 1/x at x = 3. (And so it equals -1/9).

 

[Rainmaker]

Wait.. you divided by zero?

LOL!

You people are scaring me with your weird numbers and strange calculations I'm going to go and learn what it is and how to do it, so I know for next time

 

[jr1104]

It goes to 0/0...

*World Implodes*

 

[p4radox]

Edit: L'hopitals rule says otherwise.

Do this.

Or try expanding the fractions on top into power series and simplifying.

 

[Rebelius]

the answer your looking for is probably -1/9 which can be found either by simplifying or by l'hopital's rule

however, the answer to what you asked is -3.