Maths Core 4 Revision Help

Soldato
Joined
29 Jun 2004
Posts
12,957
Hello. I need help. I know the following trig identities:

cos²A + sin²A = 1
1 + tan² A = sec² A

cos2A = 2cos²A - 1 = cos² A = 0.5(1 + cos2A)
cos2A = 1 - 2sin²A = sin²A = 0.5(1 - cos2A)
sin2A = 2sinAcosA

sin(A +/- B) = sinAcosB +/- cosAsinB
cos(A +/- B) = cosAcosB -/+ sinAsinB

Here's where the problem starts. I want to integrate the following:

1/ tan²x dx
2/ cos²3x dx
3/ sin3xcos3x dx
4/ sin²0.5x dx

Now the book i'm working from managed to convert the above using the idendities to:

1/ sec²-1 dx
2/ 0.5(1 + cos6x)
3/ 0.5sin6x
4/ 0.5(1 - cosx)

I can happily do the integrals no probs. But HOW THE HELL did they convert from the first set of integrals to the second ONLY using the above identities. I'm well and truely baffled.

Thanks! :)
 
Calder said:
1/ uses 1 + tan²x = sec²x, it just moves the +1 to the other side, giving tan²x = sec²x - 1.

2/ uses cos²x = 0.5(1 + cos2x), the example given is just the same but 3 times bigger.

3/ uses sin2x = 2sinxcosx, the example given is just the same but with different coefficients.

4/ uses sin²x = 0.5(1 - cos2x), the example given is just the same but divided in half.



Thanks for that! You've put a smile on my face! Thanks! :)

And away I go to integrate...
 
Back
Top Bottom