Maths Help

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14 Dec 2002
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Sorry to make one of these threads but could someone confirm that I've done this the right way, it's been along time since I've done differentiation velocity/acceleration etc.

Task 1 (P5 a)

a. If s= 5 + 25t – 6t², where s metres is the distance travelled in t seconds, by a body.

Determine the velocity of the body at t = 2 seconds.

Velocity (ds/dt)

(dS/dT) = 25 – 12t

when t = 2 seconds.

Velocity = 25 – (12*2)
Velocity = 25 – 24
Velocity = 1 m/s


b. The velocity (v) of a moving body is given by v = 5 +12t – 2t², where v is in m/s and t is time in sec. Determine the acceleration when t= 3 seconds.


dv/dt = 12 - 4 t

Acceleration = 12 – (4*3)
= 12 – 12
= 0 m/s



Just got a feeling I've gone about this the wrong way about these questions.

Any help would be much appreciated.
 
Cheers guys.


Just wasn't sure if I had to just differentiate the velocity formula to give me the acceleration formula. I know that you find the derivitive of the s formula for the acceleration.

:)
 
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