Maths Question

[Barks]

The answer is not between 1 or 9 this time!

I know people hate these threads but I'd honestly be extremely grateful as this has been annoying me all evening.

A = ((1 - X) ^ n) - ((1 - X) ^ (n+1))

Now apparently you can take out a common factor which is (1 - X) ^ n

And you then get A = (X(1-X) ^ n)

How on earth do you get there?

I know how to factorize it but that does not get (X(1-X) ^ n) yet plug in some values and indeed it does equal the top line.

Any ideas?

Cheers

 

[Barks]

Shouldn't need a Berkely Ring Theorist to solve this one.

 

[Barks]

going by power rules...
x^2 * x^2 = x^2+2 = x^4

(x-1)^n * (x-1)^1 = x^n+1 see where im going...


A = (1-x)^n - (1-x)^n+1

A = (1-x)^n * [1 - (1-x)]

part inside square brackets

[1 - (1-x)] = 1 - 1 - -x = 1-1+x = x
so A = (1-x)^n * [x]
or A = x(1-x)^n

Brilliant, thanks for that mate. It was the part in bold I didn't think of simplifying.

Edit - Cheers to everyone else too some of your replies weren't there when I wrote the above.