PHP Countdown timer help

craptakular · 23 Jan 2011 at 21:59

Found this cool PHP code on the interwebs which is ideal, it offers me a weekly countdown timer, but how would I adapt this to show hours left to buy a ticket on the last day?

At the moment it says tickets closed on the last day, but I want it to count down evey hour to a set time on the last day.

Can anyone help?

PHP:

<?php
 $interval = 3; // number of days between ticket sales
$launch_date = strtotime('22 January 2011'); // fill in
$days = floor((time() - $launch_date)/86400) % $interval;
if($days === 0)
{
    echo 'Ticket sales are now closed';
}
else
{
    echo '<p>Ticket sales close in '.((($days = $interval - $days)>($interval-1))?$days-$interval:$days).' days</p>';
} 

?>

craptakular · 23 Jan 2011 at 22:10

I don't want a javascript one, I'm more than happy sticking with a server-side language.

Thanks for the pointer all the same.

craptakular · 24 Jan 2011 at 07:25

Yeh I am using php 5.3+

How would I adapt it to print the Days Hours and min on the weekly countdown?

It has dawned on me that my timers will need to be set to 15:45 every Weds or say every friday at 20:15.

So it would read:

Ticket sales close in 4 days, 21 hours, 30 mins.

Then when the counter hits 0 days 0 hours 0 mins it would display "Ticket sales are closed" for a time period that I could change. After which it would then recommence it's weekly countdown to Weds at 15:45

craptakular · 24 Jan 2011 at 18:31

I'm totally lost hehe

This is my first experience with a computer language

Would I not have to set

PHP:

$ticketdate = strtotime("25 January 2011");

to

PHP:

$ticketdate = strtotime("25 January 2011 21:00:00");

?

craptakular · 25 Jan 2011 at 15:02

My school work? I am 28 lol

craptakular · 25 Jan 2011 at 15:08

I'm at work now but will try what you suggest this evening.

craptakular · 25 Jan 2011 at 18:28

Ok can we go back to extreme basics?

PHP:

<?php 

$ticketdate = strtotime("30 January 2011");
$timediff = $ticketdate - time();

$remainDay = floor($timediff/(86400));
$remainHours = floor(($timediff-($remainDay*86400))/(3600));
$remainMins = floor(($timediff-($remainDay*86400)-($remainHours*3600))/60);

print "Target date is: $ticketdate. Time Difference is: $timediff . Ticket sales close in $remainDay days, $remainHours hours, and $remainMins mins";

 ?>

In it's very basic form, it prints the right remaining days. How would I change $ticketdate for every Friday at 14:30?

So tickets close for sale every Friday at 14:30.

craptakular · 25 Jan 2011 at 19:35

Sorry for my triple posting, didn't edit my posts so people who wish to help can see what a mess I am making

I now have a very basic working script.

PHP:

<?php 

$ticketdate =  mktime(19, 30, 0, 1, 25, 2011) ; //ticketdate is set to 25th Jan 2011 19:30
$timediff = $ticketdate - time();

$remainDay = floor($timediff/(86400));
$remainHours = floor(($timediff-($remainDay*86400))/(3600));
$remainMins = floor(($timediff-($remainDay*86400)-($remainHours*3600))/60);

if ($timediff < 0) 

    echo "Sales Closed";

else 

    echo "Target date is: $ticketdate. Time Difference is: $timediff . Ticket sales close in $remainDay days, $remainHours hours, and $remainMins mins";

 ?>

Now before I try to go further with this how do I get this to repeat each week?

My event is weekly not a one time event.

craptakular · 26 Jan 2011 at 07:09

shine said:
Your right, I just that together a while back when I was bored at work and was counting down until home time.

You did that in an afternoon? I hate you...

craptakular · 26 Jan 2011 at 10:30

iDroid84 said:
I was jesting. You resolved it yet?

Well not really, I need to change mktime to work either every Friday at 19.30

this is my first obstacle hehe

craptakular · 26 Jan 2011 at 13:15

visibleman said:
kwerk has already posted a solution to this ie: -

Code:

$ticketdate = strtotime("Friday 19:30", strtotime("now"));

You are right, I totally missed his post.

craptakular · 26 Jan 2011 at 18:11

Still having issues with this, the time keeps going negative and not resetting for the next Weds at 6pm. any ideas?

PHP:

<?php 

$ticketdate =  strtotime("wednesday 18:00", strtotime("now")) ;
$timediff = $ticketdate - time();

$remainDay = floor($timediff/(86400));
$remainHours = floor(($timediff-($remainDay*86400))/(3600));
$remainMins = floor(($timediff-($remainDay*86400)-($remainHours*3600))/60);

if ($timediff < 0) 

    echo "Target date is: $ticketdate. Time Difference is: $timediff . Sales Closed";
    
else

    echo "Target date is: $ticketdate. Time Difference is: $timediff . Ticket sales close in $remainDay days, $remainHours hours, and $remainMins mins";  

 ?>

I suspect I have to tell the script to re-read $ticketdate when timediff = 0

craptakular · 26 Jan 2011 at 21:10

It does trigger the sales closed echo but, it then doesn't reset itself and start counting down towards next wednesday at 21:10

Code:

Target date is: 1296076080. Time Difference is: -136 . Sales Closed

craptakular · 26 Jan 2011 at 21:51

Thats perfect. Thank you so much!

On line 3, have you told it that if $timediff is equal to or less than 0 to fetch the "next" strtotime which creates a loop?

Out of interested how would I go about adding in a delay of say 60 mins between change over.

i.e.

if between Weds at 7:31 - 8:30

echo tickets closed

else continue countdown

Would I need to use the time function? How do you create an if statement for a time range?

PS: You have helped me enough, feel free to tell me to go away

craptakular · 27 Jan 2011 at 08:30

Guys very good, I think I will have to use the +1 hour method tonight.

Out of interest, how would I go about counting down to two different days a week at different times?

Would I have to adapt the if statement from next to a new Ticketdate then loop it somehow?

craptakular · 27 Jan 2011 at 20:29

Will look into, I think it's going to make many months of studying for me to fully understand how you built this script let alone to get it to do multiple days per week.

Hired a few books from the library to get me started.

Thank you all so much for your pacience!

craptakular · 29 Jan 2011 at 22:47

PHP:

<?php 

// ** Countdown Function **
function ticketCountdown($ticketdate, $delay = 0) {
    $timediff = (strtotime($ticketdate, strtotime("now"))) - time();
    if ($timediff <= -$delay) $timediff = (strtotime("Next ".$ticketdate, strtotime("now"))) - time();

    if ($timediff <= 0) {
        return false; //Ticket Sale Ended
    } else {
        $remainDay = floor($timediff/(86400));
        $remainHours = floor(($timediff-($remainDay*86400))/(3600));
        $remainMins = floor(($timediff-($remainDay*86400)-($remainHours*3600))/60);

        //array[0] = remaining Day(s)
        //array[1] = remaining Hour(s)
        //array[1] = remaining Minute(s)
        return array($remainDay, $remainHours, $remainMins);
    }
}
// ** Countdown Function **

//** Countdown Routine **
$ticketSale1 = ticketCountdown("Saturday 22:40", 30);

if ($ticketSale1) {
    echo "Ticket Sale 1 - $ticketSale1[0] Days, $ticketSale1[1] Hours, $ticketSale1[2] Minutes remain<br>";
} else {
    echo "Ticket Sale 1 - Ended<br>";
}
//** Countdown Routine **

//** Countdown Routine **
$ticketSale2 = ticketCountdown("Saturday 22:43", 30);

if ($ticketSale2) {
    echo "Ticket Sale 2 - $ticketSale2[0] Days, $ticketSale2[1] Hours, $ticketSale2[2] Minutes remain<br>";
} else {
    echo "Ticket Sale 2 - Ended<br>";
}
//** Countdown Routine **

 ?>

Thats brilliant! Only Issue I have is that it prints both sets of echo's for ticketsales1 and ticketsales2.

I assume I would have to tell it to only echo ticketsales2 if ticketsales1 has passed... going to need to research this, unless you still would like to help

craptakular · 30 Jan 2011 at 14:19

Yeh I set it to 30 Seconds just to test it

What I am after is only echo'ing $tickeSales1 until it expires. When it does expire I would like the ticketSales1 echo to stop and to be replaced by targetSales2 echo

craptakular · 30 Jan 2011 at 19:57

PHP:

<?php 

// ** Countdown Function **
function ticketCountdown($ticketdate, $delay = 0) {
    $timediff = (strtotime($ticketdate, strtotime("now"))) - time();
    if ($timediff <= -$delay) $timediff = (strtotime("Next ".$ticketdate, strtotime("now"))) - time();

    if ($timediff <= 0) {
        return false; //Ticket Sale Ended
    } else {
        $remainDay = floor($timediff/(86400));
        $remainHours = floor(($timediff-($remainDay*86400))/(3600));
        $remainMins = floor(($timediff-($remainDay*86400)-($remainHours*3600))/60);

        //array[0] = remaining Day(s)
        //array[1] = remaining Hour(s)
        //array[1] = remaining Minute(s)
        return array($remainDay, $remainHours, $remainMins);
    }
}
// ** Countdown Function **

//** Countdown Routine **
$ticketSale1 = ticketCountdown("Sunday 19:53", 30);
$ticketSale2 = ticketCountdown("Sunday 19:57", 30);

if ($ticketSale2 > $ticketSale1) {
    echo "Ticket Sale 1 - $ticketSale1[0] Days, $ticketSale1[1] Hours, $ticketSale1[2] Minutes remain<br>";
} if ($ticketSale2 < $ticketSale1) {
    echo "Ticket Sale 2 - $ticketSale2[0] Days, $ticketSale2[1] Hours, $ticketSale2[2] Minutes remain<br>";
}

 ?>

Semi fixed it all on my own!!

It now only displays one $ticketSales at a time, the only issue now is that it says Days Hours Min when in the delay peroid.

If only I could get it to read "0 Days 0 Hours 0 Mins" during the delay period for both taicketsales1 and ticketsales2 I would be in business!

craptakular · 31 Jan 2011 at 17:44

Basically a countdown timer for several set days a week, which this does. However, it needs to only display one echo at a time.

so it would display the echo ticketsales1 then the $delay would kick in, changing the echo to "ticket sales closed" then when the $delay has passed for ticketsales1, it's echo would be removed and replaced with the echo's relating to ticketsales2.

Apologies for not being clear