PHP (noob)

suarve · 4 Dec 2006 at 18:57

Hi,

If i get:

Method Not Allowed

The requested method POST is not allowed for the URL /site/join.html.

when i try to run a simple php script does it mean POST has been disabled by my host (tsohost)?

Just made a very very basic script for my site that posts the info from a form onto a page, using the following:

PHP:

<? php 

define("BR", "<br />");

$name = $_POST["txtname"];
$password = $_POST["txtpassword"];
$email = $_POST["txtemail"];
$location = $_POST["optlocation"];
$age = $_POST["txtage"];
$gametypes = $_POST["optgametypes"];
$currentclan = $_POST["txtcurrentclan"];
$previousclans = $_POST["txtpreviousclans"];
$additionalinfo = $_POST["txtadditionalinfo"];

echo "Name: $name" . BR . "Password: $password" . BR . "Mail: $email" . BR . "Location: $location" . BR . "Age: $age" . BR . "Gametypes: $gametypes" . BR . "Current Clan: $currentclan" . BR . "Previous Clan: $previousclans" . BR . "Other Info: $additionalinfo";

?>

Thanks

suarve · 4 Dec 2006 at 19:14

bah, just renamed the html file to .php. I assume to script runs now as i get the following error now:

Code:

[b]Parse error[/b]:  syntax error, unexpected T_STRING in [b]/home/rallport/public_html/site/submit.php[/b] on line [b]3[/b]

suarve · 4 Dec 2006 at 19:14

bah, just renamed the html file to .php. I assume to script runs now as i get the following error now:

PHP:

Parse error:  syntax error, unexpected T_STRING in /home/rallport/public_html/site/submit.php on line 3

Any ideas?

suarve · 4 Dec 2006 at 19:24

chesterstu said:
try taking the space out between <? and php

*blushes*, thank you.

suarve · 4 Dec 2006 at 19:38

Right, thats works now and outputs the data on an unformatted page. On the original page where the form is located, everything is formatted nicely, links to css files etc. My question: how can i include the php code on this page so rtaht formatting is included - e.g. outputs on the same page. I'm kinda stuick as the form action is "submit.php".

Thanks for any help.

EDIT: just figured that out, apologies for the noob question.

suarve · 4 Dec 2006 at 20:00

Again, apologies for my noob questions, as everyone on here seems to be very knowledgeable on programming. I have declared a variable called today

PHP:

$today = date("F j, Y, g:i a");

Now, how can i show the date in 48 hours from $today ?

suarve · 4 Dec 2006 at 20:47

The above outputs: "1165363200". I'm sure i have messed up somewhere though.....