PHP Sessions

~J~

~J~

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Joined
20 Oct 2003
Posts
7,558
Location
London
Only been using PHP since last Thursday, so all this is totally new and I don't know if it's possible.

In a nushell I've got the following code in a page:

<?php

require("connect.php");



$txtAction = $_REQUEST['txtAction'];

$txtName = $_REQUEST['txtName'];



if ($txtAction == 'Find')

{

$sql= "SELECT name, town, county FROM customers WHERE name LIKE '%$txtName%'";

$result = @mysql_query($sql,$dbh) or die (mysql_error());



$num = mysql_num_rows($result);



if ($num > 0 )

{

$_SESSION["Results"]=$result;

header ('Location: findresults.php');





}

}


?>

Which, if results are found, go to another page which lists the results.

The PHP on the 'findresults' page is:

<?php

require("connect.php");



$result=$_SESSION["Results"];



while ($row = mysql_fetch_array($result))

{

$name = $row['name'];

$town = $row['town'];

$county = $row['county'];

echo "<p>$name</p>";

}





?>

But I get an error of "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in html/findresults.php on line 6"

Any ideas what I'm doing wrong, or is it not possible? I'd have thought by passing $Results in a session I'd be able to retrieve it's entireity on the calling page!
 
Doh!

OK, done that, but it only seems to work if I pass the $SQL into a session and call the database twice (which seems a bit of a hammering on the SQL Server).

Can passing the $results array not be done then?
 
Cheers Inquisitor, the SQL Injection stuff is been taken care of my one of the lads in house so I think we're covered on that thanks.

Have done what you suggested about the array and that worked a charm, so again, thanks for the tip on that one.

Even learnt how to use Explode today so I'm pretty pleased with myself!!
 
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