Question about speedstep

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I'm fairly new to overclocking so bare with me :D. I have been reading an article writen by an asus engineer about overclocking sandybridge . In this article he explains about speedstep still being used with overclocking .What i dont quite get is this

"It possible to overclock while keeping speedstep enabled and use the offset voltage method for Vcore increase this will provide the overall best in temperature and heatsink performance as well as generally efficiency and extension of the lifespan of the motherboards its components and the CPU. This is due to the Turbo Multiplier working and exucting ramping as Intel intended.
Example leaving all CStates and Speedstep enabled will allow the CPU to idle down in Vcore and frequency ( 1600MHz ) and ramp up when under load to 4.8GHz when needed."

I take it from this that when idling at 1600mhz which mine is the vcore should drope down . Mine is constant at 1.285 ,apart frome vdrope at load .

Am i misundestanding( is this a word?) things ???
 
The vcore will only drop so much because when you use the power if the volts are not there it will become unstable. Most people have speed step off because of it but looks like they have fixed it on the new socket
 
Your voltage is constant because you have probably set the voltage rather than using the voltage offset, assuming you have not disabled speedstep or any of the c states
 
Your voltage is constant because you have probably set the voltage rather than using the voltage offset, assuming you have not disabled speedstep or any of the c states

Thanks. you were right . Just reading up on voltage offsett at the moment , seems it takes more volts to get stable . So swings and rownderbouts ...
 
It shouldn't require any more voltage.

EG. if you need 1.3v to be stable @ 4GHz your stock voltage is 1.1v then you'd use an offset of + 0.2000v

Now when speedstep or C1E kicks in and lowers the voltage, the lower voltage also gets +0.2000v offset added to keep it stable at the new higher, lowered core speed. If that makes sense :)
 
It shouldn't require any more voltage.

EG. if you need 1.3v to be stable @ 4GHz your stock voltage is 1.1v then you'd use an offset of + 0.2000v

Now when speedstep or C1E kicks in and lowers the voltage, the lower voltage also gets +0.2000v offset added to keep it stable at the new higher, lowered core speed. If that makes sense :)

I'm not getting results that follow your explanation . I was stable with 4500 mhz at 1.285 v ,when setting volts manually . Now when using voltage ofsett i'm at -0.04 and i am still reading 1.310 v at full load with a vid of 1.345 . I am stable at that but need to add more negative volts to get closser to 1.285. I'm a bit confused and this isnt helping

http://hardforum.com/showthread.php?t=1578110

A lot of talk about offset voltage ..
 
The way Ive explained it above is exactly how it works on my board. (Asus P7P55D)

If your stock volts are 1.345 and you want 1.285 you need to use an offset of - 0.06 not - 0.04
 
The way Ive explained it above is exactly how it works on my board. (Asus P7P55D)

If your stock volts are 1.345 and you want 1.285 you need to use an offset of - 0.06 not - 0.04


Yep got it now . Bios gives you what it thinks is right and the offsett is used to fine tune that .. just seems for me i need slightly more volts to keep stable with this.
Told you i was new to this :o
 
Are you using LLC with this too. as LLC ups the voltage a varying amount depending on load.

I ditched LLC, as it made the system unstable under light to medium load. Just went about it the good old fashioned way :)
 
Yes i am using LLC but i am also using aditional turbo volts found under cpu power options . It works well in conjunction with LLC and voltage offset for me . I was stable at full load but not at medium load as you said.



kept getting a
bsod.jpg
on opening apps in windows . but now it seems i have the same volts and temps as manual voltage but i can now tickover at low volts as well as being stable :). i now have to see if it can last a proper test :D
 
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