22 Nov 2006 at 01:57 #1 riddler riddler Associate Joined 25 Nov 2004 Posts 1,944 i. (0.1*100)+(0.1011*100) = 100+1011 = 1111 ii. (0.10111*101)-(0.10011*101) = 100111 – 10011 = 100 iii. (0.11*100)*(0.1001*100) = 1100 * 1001 = 1101100 iv. (0.11*101)(0.1*11) = 11000 100 are all of these correct? thanks in advance
i. (0.1*100)+(0.1011*100) = 100+1011 = 1111 ii. (0.10111*101)-(0.10011*101) = 100111 – 10011 = 100 iii. (0.11*100)*(0.1001*100) = 1100 * 1001 = 1101100 iv. (0.11*101)(0.1*11) = 11000 100 are all of these correct? thanks in advance
