Quick java help.

[Dunks]

Ok, stuck on a simple piece of java using nested while loops, asking here because I can't take it anymore

Right, the problem is: I have to create a program, that 'rolls' a dice until it gets 6, when it gets a six it stops, then prompts the user to enter 0 to stop, and any positive number to continue. If you continue, it 'rolls' again until it gets another 6, then repeats the prompt. If you then enter a 0, which stops the rolling, it then must calculate the average amount of rolls to get 6, then also display the amount of rolls used in calculating the average. Using nested while loops.

What I have so far

import SE111aClasses.*;
import java.util.*;
public class Tut3_7{
public static void main(String[] args){	

GUI gui = new GUI();
Random rndm = new Random();
int number = rndm.nextInt(6)+1;
int countsix = 0;
int average = 0;
int input = 1;
int counttotal = 0;

while(input!=0)
{
	while(number!=6)
	{
	counttotal++;
	number = rndm.nextInt(6)+1;
	System.out.println(number);
	}
	countsix++;
	input = gui.getInt("Enter 0 for no, above for yes");
}
System.out.println("Average rolls for a six is:" + counttotal/countsix);
System.out.println("Rolls used to calculate the average was:" + counttotal);

}
}

It works for the first roll to 6, then when it reaches the prompt, I enter 1 and it just re-prompts again and again, without re-rolling, only seems to work when i enter 0 and it then calculates it for the first roll to 6 seemingly fine.

Help

 

[ToastedCheese]

Oops forget that, I misread the post./

 

[SiriusB]

The second while pulls out the loop when number = 6. There is nothing in your code that resets number. So it goes back to "while(number!=6)" and then leaves the loop because number = 6.

EDIT: damn, beaten

 

[Dunks]

Aha, just added:

number = rndm.nextInt(6)+1;

into the while(input!=0) loop, seems to be working fine now, I hope . Thanks

import SE111aClasses.*;
import java.util.*;
public class Tut3_7{
public static void main(String[] args){	

GUI gui = new GUI();
Random rndm = new Random();
int number = rndm.nextInt(6)+1;
int countsix = 0;
int average = 0;
int input = 1;
int counttotal = 0;

while(input!=0)
{
	while(number!=6)
	{
	counttotal++;
	number = rndm.nextInt(6)+1;
	System.out.println(number);
	}
	[COLOR="Red"][b]number = rndm.nextInt(6)+1;[/b][/COLOR]
	countsix++;
	counttotal++;
	input = gui.getInt("Enter 0 for no, above for yes");
}
System.out.println("Average rolls for a six is:" + counttotal/countsix);
System.out.println("Rolls used to calculate the average was:" + counttotal);

}
}

Edit: Loop works, but my counters are screwed

 

[JIMA]

Hi,

Can you switch the second loop around so the first thing it does is calculates the dice roll? That way you can set number = 0 just before the loop to ensure it is always entered. You could also declare "number" within the first while loop if you don't want to use it outside of the whiles.

So the inner while would look something like:

int number = 0;
while(number!=6) {
number = rndm.nextInt(6)+1;
counttotal++;
System.out.println(number);
}

If you don't want to include the 6 roll in the counttotal then you can put the increment of counttotal into an if statement or "break" before the increment if the number is 6.

Jim