24 Jul 2011 at 18:41 #1 mufc802 mufc802 Soldato Joined 1 Jul 2009 Posts 2,675 Can't remember the way of moving the power. I've got x^-2=4 which is also 1/x^2=4 what do I do to get x on it's own.
Can't remember the way of moving the power. I've got x^-2=4 which is also 1/x^2=4 what do I do to get x on it's own.
24 Jul 2011 at 18:44 #2 Nitefly Nitefly Man of Honour Joined 24 Sep 2005 Posts 37,268 mufc802 said: Can't remember the way of moving the power. I've got x^-2=4 which is also 1/x^2=4 what do I do to get x on it's own. Click to expand... You can just go straight to x = 0.5 or -0.5 surely? 0.5 x 0.5 = 0.25 1 / 0.25 = 4 Or am I being the noob? It's usually highly likely
mufc802 said: Can't remember the way of moving the power. I've got x^-2=4 which is also 1/x^2=4 what do I do to get x on it's own. Click to expand... You can just go straight to x = 0.5 or -0.5 surely? 0.5 x 0.5 = 0.25 1 / 0.25 = 4 Or am I being the noob? It's usually highly likely
24 Jul 2011 at 18:46 #3 Hxc Hxc Soldato Joined 29 Oct 2004 Posts 12,501 Location London 1/x^2 = 4 1 = 4x^2 1/4 = x^2 sqrt(1/4) = x
24 Jul 2011 at 18:49 #4 Squark Squark Soldato Joined 11 Apr 2004 Posts 11,550 Location In Christ ^ What he said
24 Jul 2011 at 18:53 #5 mufc802 mufc802 Soldato OP Joined 1 Jul 2009 Posts 2,675 Thanks, now I've got that is sqrt(1/4) just 1/2 or can it be -1/2 because in my answers it has 1/2 and -1/2.
Thanks, now I've got that is sqrt(1/4) just 1/2 or can it be -1/2 because in my answers it has 1/2 and -1/2.
24 Jul 2011 at 19:43 #6 Amleto Amleto Soldato Joined 13 Feb 2003 Posts 6,157 for any polynomial of degree N, there are are exactly N roots (when counted with correct multiplicity). Therefore a square has exactly two roots
for any polynomial of degree N, there are are exactly N roots (when counted with correct multiplicity). Therefore a square has exactly two roots
