quick trigonometry help

abc is an isoscleses triangle with |ab| = |ac| = 9


given that |<abc| = 21.7o calculate the area of the angle abc. Answer to 2 decimal places.
 
Tan x = Opposite / Adjacent so a triangle with the side opposite said angle will have length 3 and side adjacent to said angle a length 4.
 
d & e are points on a river bank 80m apart and f is a point on the opposite bank as shown in the diagram.


|<fde|= 38o and |<fed| = 65o


find |ef| correct to the nearest meter.

Find the width of the river as measured from f to the nearest metre.
 
Btw, the person who answers these will earn themselves 3 pounds sterling. Believe it or not, its my sisters homework. Failure on my part has lead to her been dropped in it, unless I can solve them in the next 5 mins.
 
some students wish to estimate the height of a tree standing on level ground. One of them stands so that the end of his shadow coincides with the end of the shadow of the tree as shown in the diagram. This student is 1.6m tall.

his friend then measures the distance shown in the diagram. A is the angle of elevation of the sun.

Find a to the correct degree

find the height of the tree correct to one decimal place.
 
the diagram shows an equilateral triangle and a square each of side 6

a is joined to c.


find |<abc| and |<bac|

find |ac| correc to one decimal place.
 
Any chance of any help for the following questions, maybe drawn up quickly in MS paint or however you wish?

A pint is on me.
 
Far too much to be at at the moment so I'll just give you this:

Silly old Harry caught a herring trawling off America (I have a dirtier version but it's not forum safe :D)

Sinθ = Opposite/Hippopotamus
Cosθ = Adjacent/Hypotenuse
Tanθ = Opposite/Adjacent

Basically use what lengths you have and get the inverse sin/cos/tan as appropriate in order to get the angle value θ.

These will only work for right angled triangles though.
 
Last edited:
Antar Bolaeisk said:
Far too much to be at at the moment so I'll just give you this:

Silly old Harry caught a herring trawling off America (I have a dirtier version but it's not forum safe :D)

Sinθ = Opposite/Hippopotamus
Cosθ = Adjacent/Hypotenuse
Tanθ = Opposite/Adjacent

Basically use what lengths you have and get the inverse sin/cos/tan as appropriate in order to get the angle value θ.

These will only work for right angled triangles though.
Click to expand...

It was many a year since I did my maths cert, i remember the sin cos tan things, but just don't know how to use them.

All sorted now though with a bit of judicious ringing up of various people. :cool:

Thanks for the information written above though, didn't realise just how out of shape I am with my math.
 
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