So, alkali metals, right...?

2 M (s) + 2 H2O (l) → 2 MOH (aq) + H2 (g)

If M is the chemical symbol for the element in Group 1 of the periodic table (lithium, sodium, potassium, rubidium, caesium, francium), do they ALL follow the same pattern?

I taught this to year 9s before xmas and that equation works for them all however mine weren't a high ability group and chemical symbols were a bit too much for them!
 
The question was whether the alkali metals from lithium to francium react according to the equation in the opening post.

eLbot said:
The answer is unfortunately both yes and no depending on what level we're discussing this at.
In the interest of science (:)) can you give us some more detail?

Aod said:
sara said:
As I understand it - Caesium and Rubidium ARE chemically more reactive - but they give off so much Hydrogen that they bounce off the water on a cloud of gas instead of hanging around and fizzbanging.
yep. the reaction is so quick and powerful that the metal is completely surrounded by bubbles of gas allowing the sample to react quite slowly, actually.
I'm stating the obvious here, but this didn't seem to be the case in Vinni3's YouTube link. Lithium to potassium are less dense than water and thus float; rubidium and caesium are denser and would sink.

flibbage0 said:
The reason why they get more reactive is because as you go down group 1 in the periodic table, the number of shells increases and so does the shielding and atomic radius also increases.
Okay it's late but I don't think that even in layman's terms this provides a suitable answer as written. I got to see the demonstration for myself in year 9 but I don't recall the depth of the explanation and right now I can't think of how I would explain it without invoking electronic configurations.

The reaction is very favourable since the loss of the lone valence electron affords a noble gas configuration. It seems logical that increased reactivity corresponds to the rate at which the reaction proceeds; it might not be necessarily true that caesium has more energy to give out than lithium but it does so in a shorter timespan. Possibly for a couple of reasons the activation energy decreases on decending the group and for simplicity we could just consider the ionisation energy which decreases as that valence electron is, relatively speaking, much further away and less tightly held. Now, with an increase in reaction rate prescribed for a decrease in activation energy we can justify the observations.
 
Okay it's late but I don't think that even in layman's terms this provides a suitable answer as written. I got to see the demonstration for myself in year 9 but I don't recall the depth of the explanation and right now I can't think of how I would explain it without invoking electronic configurations.

As far as year 9 go it doesn't need to be in any depth really, they just need to know that a metal + water -> salt + hydrogen and then how to name the salt.
 
As far as year 9 go it doesn't need to be in any depth really, they just need to know that a metal + water -> salt + hydrogen and then how to name the salt.
I wouldn't refer to MOH as a salt, I'd reserve that for the product of reaction between a metal and a mineral acid.

On reflection what I wrote could be far beyond the scope of an introductory GCSE level class. The way the thread developed from a simple "is this right?" to offering explanations seems to me a bit like the Bad Translator thread where the input gets scrambled along the way :)

What would you say when one of the students asks why it's happening?
 
'Outside the laboratory, francium is extremely rare, with trace amounts found in uranium and thorium ores, where the isotope francium-223 continually forms and decays. As little as 20–30 g (one ounce) exists at any given time throughout the Earth's crust'
 
The reaction is very favourable since the loss of the lone valence electron affords a noble gas configuration. It seems logical that increased reactivity corresponds to the rate at which the reaction proceeds; it might not be necessarily true that caesium has more energy to give out than lithium but it does so in a shorter timespan. Possibly for a couple of reasons the activation energy decreases on decending the group and for simplicity we could just consider the ionisation energy which decreases as that valence electron is, relatively speaking, much further away and less tightly held. Now, with an increase in reaction rate prescribed for a decrease in activation energy we can justify the observations.

I do A2 chemistry at the moment so I think my explanation is valid enough.
 
flibbage0,
I wasn't questioning your credentials and I'd be surprised if you're the only member of the forum who's qualified to GSCE or AS level in combined science or Chemistry.

I only added I was of the opinion that, as written, attempting to explaining the increase in reactivity as being due to an increased number of shells, an increase in shielding and an increase in atomic radius tells the reader nothing about what reactivity fundamentally is. It's like it is just shy of telling you the immediate consequence of those factors, that's all.
 
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