Sunday chemistry questions

tres

tres

tres

Soldato
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1) What is the oxidation number of N in the mercury (II) compound Hg(NH3)2Cl2

Would love it if someone could explain it to me please!
 
-3
The (NH3) part has a overall charge of 0.

hydrogen has a Oxidization number of +1, and there are 3 of them

3*1 - 3 = 0

or something like that
 
Thank you ripped (and so close physichull..)

So it's as simple as that.. the amine = 0, so it must be -3. No taking into account the Hg or Cl2?
 
tres said:
Thank you ripped (and so close physichull..)

So it's as simple as that.. the amine = 0, so it must be -3. No taking into account the Hg or Cl2?
Click to expand...

Well I think because Hg is in the same group as Zn, it will only form +2 ions so has an oxidation state of +2.

Each Chlorine will be -1, so that makes -2.

NH3, N will be -3.

Remember that even though the oxidation state of Cl2 is 0, it isn't when it is in a compound.
 
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