Each letter in the range A through J has a distinct value in the range 1 through 9, inclusive.
The horizontal and vertical totals are shown. Solve for all values.
EDIT: Well done.
Correct, FULL, solutions received from:
kaiowas, Shmo, Greebo, Anominity, Nazca, mp3duck, Angilion, Aero, wilko49, Cat_In_Pyjamas, div0
Correct, brute forced, solutions received from:
Garee, 23JMZ07
EDIT: SPOILER ALERT! If you don't want to see the solution, avert your gaze now!
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1st column, d+d+f+j = 8. If d=3 then 3+3+2+1 = 9. Therefore d < 3
1st row and 3rd column, a+b+c+d=18 > a+b+c+f=17. Since a+b+c is common to both equations, we can simplify to d > f. Therefore d=2 and f=1 and g=6 and j=3
4,5,7,8,9 remaining
2nd column / 4th row, a+e=12 could be either 4+8 or 5+7
2nd row / 4th column, e+c+h=22 can only be 5+8+9
E is common to both equations as are 5 and 8, so e is equal to either 5 or 8.
If e=5 then a=7 leaving 4,8,9 remaining which means bc=9, but no comination of the remaining 3 numbers is equal to 9. Therefore e=8 and a=4
5,7,9 remaining
1st row / 3rd column, b+c=12 can only be 7+5
2nd row / 4th column, c+h=14 can only be 5+9
c is common to both equations as is 5, therefore c=5 and b=7 and h=9
a=4
b=7
c=5
d=2
e=8
f=1
g=6
h=9
j=3
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