Trigonometry help

[D.Roberts]

Hi all I know for some this will be easy..for me I was never good at maths.

I want to find out the formula used to find

b

I know a is 352
I know c is 1520

the answer is 1478 there about

this is the calculator I used

http://www.carbidedepot.com/formulas-trigright.asp

So whats the formula in simple terms please .

I have seen loads of YouTube vids but they all do it by knowing a length of one side and an angle.

Thanks

 

[D.Roberts]

Thanks for all the help.

I feel like a ball bag.

 

[D.Roberts]

ax^2+bx+c = 0

x^2 + (b/a)x + (c/a) = 0

[x + b/(2a)]^2 - (b^2)/(4a^2) + c/a = 0

[x + b/(2a)]^2 = (b^2)/(4a^2) - c/a

[x + b/(2a)]^2 = (b^2 - 4ac)/(4a^2)

x + b/(2a) = [+/- sqrt(b^2 - 4ac)]/(2a)

x = [-b +/- sqrt(b^2 - 4ac)]/(2a)

And that is why the quadratic formula works. It's just solving for x from the initial quadratic.

What he said tbh