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What causes Vdroop?

Part of it is to do with the resistors and transistors.

They are never at the values quoted. They are always + or - about 1-5% so you never actually get *** proper value,

Past that not a clue.
 
Yeah I aint got clue either. Quite frustrating when I'm setting the Voltage to 1.45 and its reporting 1.216
 
Thats rather a large margin to be out by, whats the stock vcore for the cpu?

Indeed it is, just trying to overclock my HTPC, just for a laugh to see what I can get out of it. Its a cheap ECS mATX mobo with an e6320 in it, so probably the mobo aint helping matters.

Stock volts reporting as 1.325.
 
HOLY CHRIST..!! Might have to go dig up Mr Einstien to come and translate that into Yorkshire for me.

Understood some of it and skipped some, but now I just feel thick...:D

The summary is it's there by design but due to design differences and tolerances the vdroop will and does vary even on the same model mobo and mobo manufacturers :D
 
Resistance?

Simple: A cpu is udner more load, generating more heat ( wich is electricity going to waste into heat) thus resistance and the voltage drops because of this because the mobo doesn't raise the volts supply enough to keep voltage as it was with the cpu idling.

Renember, energy never goes away, it's just transformed between power(as in elec)/heat/light/movement, etc...
So all the heat that is generated at the cpu is electricity being converted to heat instead of staying electricity.
 
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vDroop on LGA775 boards is designed to happen as per Intel specifications, someone posted a link earlier but it's a safety implementation so that the dynamic vcore doesn't over shoot the mark when the system goes under load.

Certain motherboards have bios options to disable the circuitry that implements this.
 
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