Zenity and bash script, help please!

[Malt_Vinegar]

Hi Guys,

Trying to knock up a script to change a variable, depending on answers:

#! /bin/bash
ans=$(zenity --list --text "Select your Domain" --radiolist --column "Pick" --column "Domain" TRUE UK FALSE US FALSE EUR);
if (( $ans == US ));
then
setparam ica.pnlogin.browseraddress_store1.server US.cloud.com:443
.
elif (( $ans == UK ));
then
setparam ica.pnlogin.browseraddress_store1.server UK.cloud.com:443
.
elif (( $ans == EUR ));
then
setparam ica.pnlogin.browseraddress_store1.server EUR.cloud.com:443
.
fi

This is where I have got to, but its not working correctly! The "setparam" command does work, and if i just have an Else/IF with two options, it seems to work fine. However, I will have 3+ options to use in this scenario, and I am tweaking away like mad and failing.

I am new to bash scripting, so be gentle please

 

[AmateurExpert]

Firstly - use single or double square brackets [] [[]] for your test expressions not double round brackets - the latter only applies for numeric expressions. I think this Linux Academy article is quite helpful.

Secondly - bash has the case keyword for multiple options - look it up, as it should result in easier to read code.