A math puzzle for you!

[ntg]

alright,


Let's say n=m,

Then nm=n^2

Then we just choose to subtract m^2 from both sides (it doesn't affect the equation) nm-m^2=n^2-m^2

Then we got m(n-m)=(n-m)(n+m)

Let's go on and divide with n-m and we have

m(n-m)/(n-m)=(n-m)(n+m)/(n-m) which gives us

m = n+m,

since n=m this means that m=2m

If we divide by m both sides then 1=2.

So what's wrong with this???

 

[TheMightyTen]

Sorry, I only do maths puzzles.

 

[rypt]

Let's go on and divide with n-m and we have

You are dividing by 0

 

[mavers]

you cant divide by 0 ( as n-m = 0)
hence this isnt mathematically valid

 

[Hxc]

Divide by zero.

 

[rypt]

you cant divide by 0 ( as n-m = 0)
hence this isnt mathematically valid

Divide by zero.

slooooow

 

[ntg]

That was faster than I expected!

 

[rz30]

m cannot equal 2m

You said m=2m it can't it equals m only.

You equations are flawed.

 

[Mason-]

m(n-m)/(n-m)=(n-m)(n+m)/(n-m) which gives us


at this part change every m to an n because n = m
n(n-n)/(n-n) = (n-n)(n+n)/(n-n)

so you have
0/0 = 0/0

You've just rearranged everything into nothing. Why would you want to do this anyway?
n = m
nm = n^2
so nn = n^2
n^2 = n^2

I don't see why you're rearranging stuff that just equals itself.

 

[markweatherill]

Well, 1=2 is wrong.

 

[Garee]

*Insert overused divide by zero picture*

 

[RadoX]

Cannot divide by zero.

 

[Mucky_Pup]

42.

 

[Ziggy]

That was faster than I expected!

Everyone's seen it before.

 

[int]

1 = 3/3

1/3 = 0.3 recurring
0.3 recurring * 3 = 0.9 recurring

Therefore 1 = 0.9 recurring

My maths teacher always used to pull this out, quite silly really.

 

[rypt]

*Insert overused divide by zero picture*

Ok

 

[Combat squirrel]

42.

 

[Six6siX]

Therefore 1 = 0.9 recurring

FUUUUUUUUUUUUU

 

[ntg]

1 = 3/3

1/3 = 0.3 recurring
0.3 recurring * 3 = 0.9 recurring

Therefore 1 = 0.9 recurring

My maths teacher always used to pull this out, quite silly really.

So? 0.9999recurring IS actually equal to 1, it's not a fallacy or inequality.

The proof is simple really as let x = 0.3333333
10x = 3.333333
subtract x
10x-x = 3.333333-0.333333
9x=3
3x=1, so 3*0.333333333 = 1

0.x recurring is accepted in maths that it is equal to an integer.

 

[TheCenturion]

if n=m
then 1 cannot equal 2 because then n and m are not the same