mavity energy?

It wouldn't, but it'd come close to it. Some heat would escape so it'd all be water.

EVH - it also needs me to post another thread after that to try and get some irony, then people to either spot it right away or not at all. Have a go at me. And then the morning crew who missed the whole thing to have a go at me too!
 
Yes, because you can't isolate the ice and water from the environment.

If you COULD isolate them... then I think it'd be water still, as water doesn't freeze at exactly 0.
 
salami1212 said:
damnit.. Ok, another one for you all.

If you had a block of ice at -50 degrees celcius and you popped it in a bucket which was the same amount of water as the ice but it was at 50 degrees celcius would the water freeze or melt?
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If it was a completely closed system (ie no heat or energy lost/gained) then if everything was perfect the water temperature would probably hit 0. Whether 0 (as opposed to -0.01) is when water freezes is another question.

In reality it would depend on how cold the room was outside. If it was warmer than 0 then it would all melt, if colder then it would all freeze.

As for how it would work I assume the edges of the ice cube would melt, cooling the water surrounding the cube down until it stated to freeze again, slowly rippling out as it goes along, then either freezing or melting entirely depending on my first paragraph.
 
The Halk said:
It wouldn't, but it'd come close to it. Some heat would escape so it'd all be water.

EVH - it also needs me to post another thread after that to try and get some irony, then people to either spot it right away or not at all. Have a go at me. And then the morning crew who missed the whole thing to have a go at me too!
Click to expand...

You started a follow on thread? Brave man.

Linkage. I could do with the lulz. Again.
 
Castiel said:
No, each time the ball bounced it would shed energy.

If you can solve the problems surrounding a perpetual motion machine then you will become a very rich and famous young man.


I don't have high hopes of that however.
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Easy. Just assume it's an ideal system: restrict the system to vertical motion, neglect drag, use a perfectly incompressible ball, and make sure its collision with the spring is perfectly elastic. Voila: perpetual motion! Excuse me while I claim my Nobel prize :cool:
 
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Amp34 said:
If it was a completely closed system (ie no heat or energy lost/gained) then if everything was perfect the water temperature would probably hit 0. Whether 0 (as opposed to -0.01) is when water freezes is another question.

In reality it would depend on how cold the room was outside. If it was warmer than 0 then it would all melt, if colder then it would all freeze.

As for how it would work I assume the edges of the ice cube would melt, cooling the water surrounding the cube down until it stated to freeze again, slowly rippling out as it goes along, then either freezing or melting entirely depending on my first paragraph.
Click to expand...

so theres no definitive answer really. If there was zero way the temperature could be affected and the water was Exactly the same then it would either freeze or melt depending on which side of 0 water freezes on?
 
salami1212 said:
temperature wise?
and 0 heat can escape because its in a special bucket.
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in that case, it'll be a bucket of water.

Water does defrost & freeze at 0 (assuming it's pure water) The only difference is, when freezing water, more energy needs to be removed to change water at 0C, into ice at 0C. Same works the other way. When melting ice, you need to put more energy in to change ice at 0C into water at 0C (the change doesn't happen instantly)
 
Inquisitor said:
Easy. Just assume it's an ideal system: restrict the system to vertical motion, neglect drag, use a perfectly incompressible ball, and make sure its collision with the spring is perfectly elastic. Voila: perpetual motion! Excuse me while I claim my Nobel prize :cool:
Click to expand...

Spoken like a true physicist ;)
 
Whilst on the subject, what happened to Steorn's Orbo? Last I heard, after there failed first demo, they revised their design by adding a battery to the circuit.
 
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