Really easy maths question...

Soldato
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Hello,

Just attempting one of my c1 papers I've had to do over the holidays and there is one question which is really stumping me... I have looked over it and convinced I have the right answer but the markscheme says otherwise :/

Question is solve the simultaneous equations

x+y=2 and 3x^2-2x+y^2=2

So you sub in y=2-x into the 2nd equ and then need to expand

3x^2-2x+(2-x)^2=2

To which I get:
2x^2-6x+2=0

But the markscheme says:
2x^2-3x+1=0

What am I doing wrong? Someone explain pleeeease :)

Cheers guys
 
The mark scheme is correct.

x+y=2
3x^2-2x+y^2=2

From Eq 1, y=2-x

Substitute into Eq 2.

3x^2-2x+(2-x)^2=2

Which becomes

3x^2-2x+4-4x+x^2=2

Which reduces to

4x^2-6x+2=0

Which cancels down to

2x^2-3x+1=0
 
Last edited:
It's really not hard. Write it down on some scrap paper and you'll see it's a piece of cake.

Maths is not my strong point, thats what calculators are for, if I can't work something out, e.g how much something costs in a foreign country, I just pull out my biggest note lol
 
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