If you choose an answer to this question at random, what is the chance you will be correct?

I think you have a 1/3 chance of getting it right.

There's 3 possible answers, so 1/3? Yes.

Your on the right lines, but don't forget you are more likely to pick the duplicate answer, since you are picking at random you have a higher chance to pick one of them.
 
33.3(recurring)% or 1/3?

You have a 25% chance of answering A,B,C or D if you choose one of them at random.

Given we don't know what question the answers relate to and there are only 3 potential answers then the chance of any of the answers being correct is 1/3.

Therefore

25% * 1/3
+
25% * 1/3
+
25% * 1/3
+
25% * 1/3

= 1/3 or 33.3(recurring)%

However, if the answers are related to the chance of getting this question correct then it becomes a mathematical paradox.
 
Struggling to see how it can be anything other than 0% really.

The probability of picking an answer of 25% (A or D) is 50% - but since picking either A or D gives an answer of 25% this doesn't tally with the 50% chance of getting A or D.

It can't be B because there's a 25% chance to pick B which doesn't tally with the answer of 50% that B gives.

And it can't be C for the same reason - 25% chance to pick C which doesn't tally with the answer of 60% that B gives.

I predict the true answer will probably fry my brain though.
 
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