Can anyone figure this out

One of the 2 leftmost?
If the guy on the far left can see 2 hats the same in front, he can obviously shout what colour his hat is.
If he doesnt shout, the guy in front of him knows that the guy behind can see 2 different hats, so he will know the colour of his own hat.

...but this relies on them being able to communicate with each other, so it would be easier to just ask the guy behind what colour their hat is.
 
second from the left

far left can plainly see 2 hats of diffent colors so does not know for sure what color his is.

far right can't see anybody and niether can second from the right.

second from left can see second from right and knows it's black he also knows that far left can see two hats so if he does not call out he knows he sees two different colors that means he is wearing white
 
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One of the 2 leftmost?
If the guy on the far left can see 2 hats the same in front, he can obviously shout what colour his hat is.
If he doesnt shout, the guy in front of him knows that the guy behind can see 2 different hats, so he will know the colour of his own hat.

...but this relies on them being able to communicate with each other, so it would be easier to just ask the guy behind what colour their hat is.

what is it with you and puzzle solving :eek:

they can't talk to each other, but they would as you suggest hear if someone confidently shouted out [and the gunshot if they were wrong].
 
Ok I shall stop being stupid because it is kind of obvious. If the one on the left is A then next B then C then wall then D then:

If A sees B and C with the same he knows what he is.
If A sees B and C different then he won't shout out.
Therefore, if B hears nothing from A then he knows that he and C are different therefore he is opposite to C.

Please tell me that is right!
 
Ok I shall stop being stupid because it is kind of obvious. If the one on the left is A then next B then C then wall then D then:

If A sees B and C with the same he knows what he is.
If A sees B and C different then he won't shout out.
Therefore, if B hears nothing from A then he knows that he and C are different therefore he is opposite to C.

Please tell me that is right!

yes
 
ok, how about a harder one [and when i say hard, it was given to me by a german engineer who explained the answer and i still couldn't figure out how he got it]



the ladder is 7m long

the box is 1m high by 1m wide

how high up the wall is the ladder?

if you know your trig try telling me the angle it is from the floor too.

as i said, i don't know the answer to this, so your flying blind folks but i recall it sounding relatively simple [ie not full blown calculus or anything]

edit: scratch that, remember how he started it at least.

hint:
graph's a toy

answer that i'm too tired to try to understand:

that may* have been slightly harder than i remember it being, there's no shame in not getting it, even after you've seen the answer, i know i havent got it yet and i set the puzzle :D

*read: definately
 
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that one is way over my head I know it uses Pythagorean Theorem but I don't understand it

I will say though there are two different heights at which the ladder will touch the wall, the box and the floor all at the same time, I'm assuming you want the higher of the two.
 
not gonna lie i did cheat to get this because to be quite frank if i did it genuinley it'd probably be wrong in any case, so here's what solid edge says about xordium's answer:

wrong i'm afraid, it's 6.09 for my example with the 7m ladder according to the computer
 
I can't be bothered to do it again when there are clever maths people who could do it in 5 seconds and actually press the right buttons on a calculator but I was saying:

Height = 1 + y
Width = 1 + x
Ladder of course = 7

Therefore: 49 = (1+x)2 + (1+y)2

Then I think self similar triangles to say y = 1/x then putting that in multiplying by x2 etc etc etc

Guess I took a big wrong turn along the way! I am thinking you could do it maybe better with angles but like I said it's late and I won't get anything correct this time of night.
 
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