Poll: 6÷2(1+2)

[SS-89]

It's 9, simple BODMAS.

Expand the inside of the brackets and apply it to the expression leaves:

6/2*(3) = 3*3 = 9.

 

[vincent1989]

Yes you do the brackets first, but you do the contents of the brackets first, then "remove" the brackets and carry on applying BODMAS.

So it becomes,

6 / 2 * (1 + 2)
6 / 2 * (3)
6 / 2 * 3
3 * 3
9.

6/((1+2)+(1+2))

or

or 6÷2(1+2)
6 / (2+4)
6 / 6
= 1

A* at GCSE would suggest i wasn't exactly talking out my arse btw 'Haircut'.

6
_____
2(1+2)

also gives 1 and it's framed the same way as the question in the op

 

[Spleenus]

Answer is 1 as has been mentioned 6 is one expression and 2(1+2) is another expression. Plus my scientific graphic calculator has worked it out as 1.

 

[Django x2]

Just please, how could it ever be 1?

 

[Strife212]

It's certainly not 1...

 

[muon]

Bidmas is clearly fallible if people are justifying an answer of nine with it.

6÷2(1+2)

6 is ONE term.
2(1+2) is ANOTHER term.

In order to achieve a result of 9 you would need:
6(1+2)÷2

It is entirely possible this problem was introduced to highlight the flaws of the BIDMAS rule.

You're reading it as

6÷(2(1+2))

That second set of brackets isn't given. It isn't one term.

 

[Mr C]

I find it easiest to explain by introducing X into the equation

6÷2(1+2) = X
2(1+2) = 6X
2+4 = 6X
6 = 6X
1 = X

It has been a long long time since i've ever done any math though.

 

[SS-89]

You're reading it as

6÷(2(1+2))

That second set of brackets isn't given. It isn't one term.

+1
This is why people are getting confused.

 

[vincent1989]

I find it easiest to explain by introducing X into the equation

6÷2(1+2) = X
2(1+2) = 6X
2+4 = 6X
6 = 6X
1 = X

It has been a long long time since i've ever done any math though.

no, that's correct as far as my education went as well.

 

[Haircut]

A* at GCSE would suggest i wasn't exactly talking out my arse btw 'Haircut'.

I see your A* at GCSE and raise you an A at A-Level and a maths degree

Unless I'm misunderstanding something in what you're saying, you're finished with the brackets once you have worked out the contents.

6 / 2 * (1+2) is exactly equivalent to 6 / 2 * 3

 

[qqg3]

when you dont know... put in variables so you dont get confuse with numbers or misdirection with poor logic...

6/x(1+2) y/x(a+b) where a,b are constants so a,b = 1,2 respectively

thefore...

y/x(1+2) = y/x(3) = y/3x

 

[Barks]

You're reading it as

6÷(2(1+2))

That second set of brackets isn't given. It isn't one term.

That would only be required to justify the elementary rules of BODMAS.

2(1+2) is one term. (2(1+2)) is not required.

 

[Strife212]

Can't tell if people are trolling or not

 

[Nitefly]

I personally would have plumped for 1.

I find it easiest to explain by introducing X into the equation

6÷2(1+2) = X
2(1+2) = 6X

Perhaps my maths skills are failing terribly, but I'm a bit confused, how does multiplying (6÷2(1+2)) by 6 equal 2(1+2)

 

[muon]

---

 

[Viper²]

Jesus, there are a lot of stupid people in this thread.

 

[QlimaxUK]

when your given numbers in (brackets) put aside other numbers with no /*-+ then default action is to multiply those numbers (also the sums in the brackets must always be done 'first' or if everything is put into brackets then they are to be done seperate)..ok in this one it dosn't make a difference but in other sums it can make a big difference)

A=9

 

[Spleenus]

That would only be required to justify the elementary rules of BODMAS.

2(1+2) is one term. (2(1+2)) is not required.

I'm in full agreement with you. The fact that the equation is shown as 6 / 2(1+2) implies that 2(1+2) needs to be equated first as it is not multiplied separately but 2(1+2) is one expression.

It is also confirmed by the below expression

6÷2(1+2) = X
6 = 2(1+2)X
6 / 2 = (1+2)X
3 = 3X
1 = X

 

[Morba]

6/2(1+2)
6/2(3)
6/2x3
6/2 = 3
3x3= 9

No?

 

[Lopéz]

I personally would have plumped for 1.



Perhaps my maths skills are failing terribly, but I'm a bit confused, how does multiplying (6÷2(1+2)) by 6 equal 2(1+2)

He's moving the 6 to the other side of the equation and making it a multiplying factor of X to cancel it out on the other side of the equation, simplifying it.