Assembler Language

[mleanz1]

Does anyone know or to work at whether a register value in assembler is odd or even?

 

[Blackvault]

Surely it will be hex, so you'll need to convert it to two's compliment binary. So the MSB (most signifcant bit) will be 1 for neg and 0 for postive.

Blackvault

 

[BullBoyShoes]

asembley language for what system>?

I would divide it by 2 and see if there is a remainder

 

[Shadez]

asembley language for what system>?

I would divide it by 2 and see if there is a remainder

no such thing as divide in most assembler languages, well not the ones i use

 

[daz]

Convert to binary and then see if the last bit is 1 or 0 ?

 

[Shadez]

Convert to binary and then see if the last bit is 1 or 0 ?

yep its that simple, the LSB is always 1 when its odd and 0 when its even

1 = 0001
2 = 0010
3 = 0011
4 = 0100
5 = 0101
6 = 0110
7 = 0111
8 = 1000
9 = 1001
A = 1010
B = 1011
C = 1100
D = 1101
E = 1110
F = 1111

Its been awhile but its probably something like this


MOVF SOMEREGISTER,W
BTFSS W,0
GOTO EVEN
//add odd code here
GOTO END
EVEN:
//add even code here
END:

 

[BullBoyShoes]

no such thing as divide in most assembler languages, well not the ones i use

( x >> 1) == (x / 2)

but yes the above is a lot simpler!

 

[mleanz1]

Cheers guys LSB is the answer