bit of maths help

Also this would be

f(x) = e^(3x-1).(3x+5)^3

f'(x) = 3e^(3x-1).(3x+5)^3 + e^(3x-1).3.3.(3x+5)^2

edit:

http://forums.overclockers.co.uk/showpost.php?p=14346858&postcount=22

Did you do A-level Maths? This is like the first thing you learn.



Also in this thread http://forums.overclockers.co.uk/showthread.php?t=18020834&highlight=username_mattheman

you say that you got a job as an analyst in fixed income and derivative markets and you can't even differentiate?

iam trying to remember this stuff.
 
charliemathworldtshirt.jpg
 
here are some other examples that might help you understand

f(x) = sin(3*x), f'(x) = 3*cos(3*x)

f(x) = e^(sin(x)), f'(x) = cos(x)*e^(sin(x))

basically, you have a function inside another function,

e being the exponential function, 3x^2 being the function side the exponential function

is the case of f(x) = e^(3*x^2), this can be written as the 2 seperate function such that f(x) = g(h(x)). g(x) = e^x and h(x) = 3*x^2

using the general formula f'(x) = h'(x)*g'(h(x))
g'(x) = e^x
h'(x) = 6*x

another way of putting it would be to differentiate the bit inside, and this is what you multiply the initial function by once you have differentiated that
 
here are some other examples that might help you understand

f(x) = sin(3*x), f'(x) = 3*cos(3*x)

f(x) = e^(sin(x)), f'(x) = cos(x)*e^(sin(x))

basically, you have a function inside another function,

e being the exponential function, 3x^2 being the function side the exponential function

is the case of f(x) = e^(3*x^2), this can be written as the 2 seperate function such that f(x) = g(h(x)). g(x) = e^x and h(x) = 3*x^2

using the general formula f'(x) = h'(x)*g'(h(x))
g'(x) = e^x
h'(x) = 6*x

another way of putting it would be to differentiate the bit inside, and this is what you multiply the initial function by once you have differentiated that

so y=e^3x = y'=3e^3x so y'' 9e^3x
this answer is right just checked it .
 
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Next time, just post a scan of the question. You really should have textbooks for this sort of thing though, they're not complicated questions.
 
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